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200 liters of a mixture contains 20% water and the rest is milk. How many liters of milk should be added to the mixture, so that the resultant mixture will have 90% milk?
  • a)
    120 liters
  • b)
    150 liters
  • c)
    180 liters
  • d)
    200 liters
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
200 liters of a mixture contains 20% water and the rest is milk. How m...
Milk in the initial mixture = 80%
Milk in the final mixture = 100% – 10% = 90%
10% : 10% = 1 : 1

Hence, Option D is correct.
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Community Answer
200 liters of a mixture contains 20% water and the rest is milk. How m...
Understanding the Mixture
We start with 200 liters of a mixture containing 20% water and 80% milk.
- Water in the mixture: 20% of 200 liters = 40 liters
- Milk in the mixture: 80% of 200 liters = 160 liters
Objective
We need to determine how much milk should be added so that the final mixture contains 90% milk.
Setting Up the Equation
Let "x" be the amount of milk added to the existing mixture. After adding x liters of milk, the new total volume of the mixture becomes:
- Total volume of mixture = 200 + x liters
The amount of milk in the new mixture will be:
- Total milk = 160 + x liters
For the resultant mixture to have 90% milk, we can set up the following equation:
- (Total milk) / (Total volume of mixture) = 90%
Substituting the values, we have:
(160 + x) / (200 + x) = 0.9
Solving the Equation
Cross-multiplying gives:
160 + x = 0.9(200 + x)
Expanding and simplifying:
160 + x = 180 + 0.9x
Now, rearranging the equation:
160 + x - 0.9x = 180
0.1x = 20
x = 200 liters
Conclusion
To achieve a mixture that is 90% milk, you need to add 200 liters of milk to the existing mixture. This shows that the correct answer is option 'D'.
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