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If A and B are two events such that P(A) = 0.3 and P(B) = 0.9 and P(B|A) = 0.6,then P(A|B) = ……​
  • a)
    0.1
  • b)
    0.5
  • c)
    0.36
  • d)
    0.2
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
If A and B are two events such that P(A) = 0.3 and P(B) = 0.9 and P(B|...
Given, P(A)=0.3, P(B)=0.9, P(B|A)=0.6, 
We know that  P(B|A)=P(A ∩ B)/P(A) implies P(A ∩ B)=P(B|A).P(A)
Therefore, P(A ∩ B)=0.6*0.3=0.18. Now P(A|B)=P(A ∩ B)/P(B)  implies P(A|B)=0.18/0.9=0.2. So, Correct option is 'D' .
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Community Answer
If A and B are two events such that P(A) = 0.3 and P(B) = 0.9 and P(B|...
To find the probability of event A given event B, we can use Bayes' theorem which states:

P(A|B) = (P(B|A) * P(A)) / P(B)

Given:
P(A) = 0.3
P(B) = 0.9
P(B|A) = 0.6

Let's substitute these values into Bayes' theorem to find P(A|B):

P(A|B) = (P(B|A) * P(A)) / P(B)
P(A|B) = (0.6 * 0.3) / 0.9
P(A|B) = 0.18 / 0.9
P(A|B) = 0.2

Therefore, the probability of event A given event B, P(A|B), is 0.2 or 20%.

Explanation:
To understand why the correct answer is 0.2, let's break down the problem and analyze the given information:

1. P(A) = 0.3
This tells us the probability of event A occurring independently.

2. P(B) = 0.9
This tells us the probability of event B occurring independently.

3. P(B|A) = 0.6
This tells us the probability of event B occurring given that event A has already occurred.

To find P(A|B), we need to determine the probability of event A occurring given that event B has already occurred. This can be calculated using Bayes' theorem.

Bayes' theorem states that the probability of event A given event B is equal to the probability of event B given event A multiplied by the probability of event A, divided by the probability of event B.

In this case, we have P(B|A), P(A), and P(B), so we can substitute these values into Bayes' theorem to find P(A|B).

After substituting the given values, we get:

P(A|B) = (0.6 * 0.3) / 0.9
P(A|B) = 0.18 / 0.9
P(A|B) = 0.2

Therefore, the probability of event A given event B, P(A|B), is 0.2 or 20%.

The correct answer is option D) 0.2.
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If A and B are two events such that P(A) = 0.3 and P(B) = 0.9 and P(B|A) = 0.6,then P(A|B) = ……​a)0.1b)0.5c)0.36d)0.2Correct answer is option 'D'. Can you explain this answer?
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