If A and B are two events such that P(A) = 0.3 and P(B) = 0.9 and P(B|...
Given, P(A)=0.3, P(B)=0.9, P(B|A)=0.6,
We know that P(B|A)=P(A ∩ B)/P(A) implies P(A ∩ B)=P(B|A).P(A)
Therefore, P(A ∩ B)=0.6*0.3=0.18. Now P(A|B)=P(A ∩ B)/P(B) implies P(A|B)=0.18/0.9=0.2. So, Correct option is 'D' .
If A and B are two events such that P(A) = 0.3 and P(B) = 0.9 and P(B|...
To find the probability of event A given event B, we can use Bayes' theorem which states:
P(A|B) = (P(B|A) * P(A)) / P(B)
Given:
P(A) = 0.3
P(B) = 0.9
P(B|A) = 0.6
Let's substitute these values into Bayes' theorem to find P(A|B):
P(A|B) = (P(B|A) * P(A)) / P(B)
P(A|B) = (0.6 * 0.3) / 0.9
P(A|B) = 0.18 / 0.9
P(A|B) = 0.2
Therefore, the probability of event A given event B, P(A|B), is 0.2 or 20%.
Explanation:
To understand why the correct answer is 0.2, let's break down the problem and analyze the given information:
1. P(A) = 0.3
This tells us the probability of event A occurring independently.
2. P(B) = 0.9
This tells us the probability of event B occurring independently.
3. P(B|A) = 0.6
This tells us the probability of event B occurring given that event A has already occurred.
To find P(A|B), we need to determine the probability of event A occurring given that event B has already occurred. This can be calculated using Bayes' theorem.
Bayes' theorem states that the probability of event A given event B is equal to the probability of event B given event A multiplied by the probability of event A, divided by the probability of event B.
In this case, we have P(B|A), P(A), and P(B), so we can substitute these values into Bayes' theorem to find P(A|B).
After substituting the given values, we get:
P(A|B) = (0.6 * 0.3) / 0.9
P(A|B) = 0.18 / 0.9
P(A|B) = 0.2
Therefore, the probability of event A given event B, P(A|B), is 0.2 or 20%.
The correct answer is option D) 0.2.