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An engine working on Carnot cycle rejects 40% of absorbed heat from the source, while the sink temperature is maintained at 27°C, then what is the source temperature?
- a)750°C
- b)477°C
- c)203°C
- d)67.5°C
Correct answer is option 'B'. Can you explain this answer?
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To find the source temperature in a Carnot cycle, we can use the Carnot efficiency formula:
Efficiency (η) = 1 - (Tc/Th)
where Tc is the temperature of the cold sink and Th is the temperature of the hot source.
In this case, we are given that the engine rejects 40% of the absorbed heat, so the efficiency is 1 - 0.4 = 0.6.
Given that the sink temperature (Tc) is 27°C, we can substitute these values into the Carnot efficiency formula and solve for the source temperature (Th).
0.6 = 1 - (27/Th)
Rearranging the equation, we get:
27/Th = 0.4
Now, we can solve for Th by cross-multiplying:
Th = 27/0.4 = 67.5°C
Therefore, the source temperature is 67.5°C.
Key Points:
- The Carnot efficiency formula is given by Efficiency (η) = 1 - (Tc/Th), where Tc is the temperature of the cold sink and Th is the temperature of the hot source.
- In this case, the engine rejects 40% of the absorbed heat, so the efficiency is 1 - 0.4 = 0.6.
- Given that the sink temperature (Tc) is 27°C, we can substitute these values into the Carnot efficiency formula and solve for the source temperature (Th).
- Rearranging the equation, we find that Th = 27/0.4 = 67.5°C.
- Therefore, the source temperature is 67.5°C.
Efficiency (η) = 1 - (Tc/Th)
where Tc is the temperature of the cold sink and Th is the temperature of the hot source.
In this case, we are given that the engine rejects 40% of the absorbed heat, so the efficiency is 1 - 0.4 = 0.6.
Given that the sink temperature (Tc) is 27°C, we can substitute these values into the Carnot efficiency formula and solve for the source temperature (Th).
0.6 = 1 - (27/Th)
Rearranging the equation, we get:
27/Th = 0.4
Now, we can solve for Th by cross-multiplying:
Th = 27/0.4 = 67.5°C
Therefore, the source temperature is 67.5°C.
Key Points:
- The Carnot efficiency formula is given by Efficiency (η) = 1 - (Tc/Th), where Tc is the temperature of the cold sink and Th is the temperature of the hot source.
- In this case, the engine rejects 40% of the absorbed heat, so the efficiency is 1 - 0.4 = 0.6.
- Given that the sink temperature (Tc) is 27°C, we can substitute these values into the Carnot efficiency formula and solve for the source temperature (Th).
- Rearranging the equation, we find that Th = 27/0.4 = 67.5°C.
- Therefore, the source temperature is 67.5°C.
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An engine working on Carnot cycle rejects 40% of absorbed heat from the source, while the sink temperature is maintained at 27°C, then what is the source temperature?a)750°C b)477°Cc)203°C d)67.5°CCorrect answer is option 'B'. Can you explain this answer?
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An engine working on Carnot cycle rejects 40% of absorbed heat from the source, while the sink temperature is maintained at 27°C, then what is the source temperature?a)750°C b)477°Cc)203°C d)67.5°CCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about An engine working on Carnot cycle rejects 40% of absorbed heat from the source, while the sink temperature is maintained at 27°C, then what is the source temperature?a)750°C b)477°Cc)203°C d)67.5°CCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An engine working on Carnot cycle rejects 40% of absorbed heat from the source, while the sink temperature is maintained at 27°C, then what is the source temperature?a)750°C b)477°Cc)203°C d)67.5°CCorrect answer is option 'B'. Can you explain this answer?.
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