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For the allotropic change represented by the equation C (graphite) → C (diamond), ΔH = 1.9 kJ. If 6 g of diamond and 6 g of graphite are separately burnt to yield CO2, the heat liberated in first case is
  • a)
     less than in the second case by 1.9 kJ
  • b)
     more than in the second case by 11.4 kJ
  • c)
     more than in the second case by 0.95 kJ
  • d)
     less than in the second case by 11.4 kJ
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
For the allotropic change represented by the equation C (graphite) &ra...
∆H given in the question is for one mole of C (g). If 6 gm of diamond and graphite are burnt in oxygen then the C (diamond) will first convert to graphite and then it will form CO2. While C (graphite) will directly form CO2. So due to the conversion of diamond into graphite, we will get extra heat. And since we have 6gm (0.5 mol) of diamond, so the heat released will be 0.5×1.9 kJ or 0.95 kJ more than the second case.
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Most Upvoted Answer
For the allotropic change represented by the equation C (graphite) &ra...
Allotrope graphite is more stable then diamond so more energy is relesed in graphite then that of diamond
answer is from b and c option now fow values
assume both are equally stable then energy released in each case will be 1.9/2= 0.95 but actually graphite is more stable so heat released will be grater than 0.95 in case of graphite......so option C
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Community Answer
For the allotropic change represented by the equation C (graphite) &ra...
To C (diamond), the enthalpy change is positive (+ΔH). This means that the conversion of graphite to diamond requires an input of energy.
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For the allotropic change represented by the equation C (graphite) →C (diamond), ΔH = 1.9 kJ. If 6 g of diamond and 6 g of graphite are separately burnt to yield CO2, the heat liberated in first case isa)less than in the second case by 1.9 kJb)more than in the second case by 11.4 kJc)more than in the second case by 0.95 kJd)less than in the second case by 11.4 kJCorrect answer is option 'C'. Can you explain this answer?
Question Description
For the allotropic change represented by the equation C (graphite) →C (diamond), ΔH = 1.9 kJ. If 6 g of diamond and 6 g of graphite are separately burnt to yield CO2, the heat liberated in first case isa)less than in the second case by 1.9 kJb)more than in the second case by 11.4 kJc)more than in the second case by 0.95 kJd)less than in the second case by 11.4 kJCorrect answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about For the allotropic change represented by the equation C (graphite) →C (diamond), ΔH = 1.9 kJ. If 6 g of diamond and 6 g of graphite are separately burnt to yield CO2, the heat liberated in first case isa)less than in the second case by 1.9 kJb)more than in the second case by 11.4 kJc)more than in the second case by 0.95 kJd)less than in the second case by 11.4 kJCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the allotropic change represented by the equation C (graphite) →C (diamond), ΔH = 1.9 kJ. If 6 g of diamond and 6 g of graphite are separately burnt to yield CO2, the heat liberated in first case isa)less than in the second case by 1.9 kJb)more than in the second case by 11.4 kJc)more than in the second case by 0.95 kJd)less than in the second case by 11.4 kJCorrect answer is option 'C'. Can you explain this answer?.
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