The numbers of the digits in a three digit number is 12. If the digits...
Understanding the Problem
To find the three-digit number based on the given conditions, let's denote the number as ABC, where A, B, and C are its digits.
Conditions Given
- The sum of the digits is 12:
A + B + C = 12
- Reversing the entire number increases it by 495:
100C + 10B + A = 100A + 10B + C + 495
This simplifies to:
99C - 99A = 495
Hence, C - A = 5
- Reversing only the ten’s and unit digits increases the number by 36:
100A + 10C + B = 100A + 10B + C + 36
This simplifies to:
9C - 9B = 36
Hence, C - B = 4
Formulating the Equations
Now we have two equations from the conditions:
1. C - A = 5
2. C - B = 4
From these, we can express A and B in terms of C:
- A = C - 5
- B = C - 4
Now substitute A and B into the digit sum equation:
(C - 5) + (C - 4) + C = 12
Solving for C
- 3C - 9 = 12
- 3C = 21
- C = 7
Now substituting C back to find A and B:
- A = 7 - 5 = 2
- B = 7 - 4 = 3
Conclusion
Thus, the three-digit number is 237.
Verification
- Sum of digits: 2 + 3 + 7 = 12
- Reversed number: 732, and 732 - 237 = 495
- Reversed tens and units: 273, and 273 - 237 = 36
All conditions are satisfied, confirming the number is indeed 237.