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A man weighs 70 kg. He stands on a weighing scale in a lift which is moving upwards with an acceleration of 5ms2.What would be the reading on the scale? (g=10 ms2)
- a)1050 N
- b)1200 N
- c)220 N
- d)1000 N
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A man weighs 70 kg. He stands on a weighing scale in a lift which is m...
As the moving elevator is a non inertial frame hence newton's laws can’t be applied directly to it. So to apply Newton's laws we need to add a pseudo force to the man's body equal to mass times the acceleration of lift in the opposite direction to that of acceleration. Thus the balancing normal force is equal to the weight of the man + mass times the acceleration which is,
Reading = Normal force = 700 + 70 x 5
= 700 + 350
= 1050 N
Reading = Normal force = 700 + 70 x 5
= 700 + 350
= 1050 N
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A man weighs 70 kg. He stands on a weighing scale in a lift which is m...
Given data:
Weight of man (W) = 70 kg
Acceleration of lift (a) = 5 m/s²
Acceleration due to gravity (g) = 10 m/s²
To find: Reading on the weighing scale
Explanation:
When the lift is moving upwards with an acceleration of 5 m/s², the man inside the lift will experience an apparent weight due to the net force acting on him. The apparent weight of the man will be greater than his actual weight when the lift is accelerating upwards, and will be less than his actual weight when the lift is decelerating or moving downwards.
The net force acting on the man can be calculated using Newton's second law of motion:
Net force (F) = ma, where m is the mass of the man and a is the acceleration of the lift.
The total force acting on the man is the sum of his actual weight and the net force:
Total force (T) = Weight of man (W) + Net force (F)
The reading on the weighing scale will be equal to the total force acting on the man.
Calculation:
Weight of man (W) = 70 kg × 10 m/s² = 700 N
Net force (F) = ma = 70 kg × 5 m/s² = 350 N
Total force (T) = W + F = 700 N + 350 N = 1050 N
Therefore, the reading on the weighing scale will be 1050 N.
Answer: a) 1050 N
Weight of man (W) = 70 kg
Acceleration of lift (a) = 5 m/s²
Acceleration due to gravity (g) = 10 m/s²
To find: Reading on the weighing scale
Explanation:
When the lift is moving upwards with an acceleration of 5 m/s², the man inside the lift will experience an apparent weight due to the net force acting on him. The apparent weight of the man will be greater than his actual weight when the lift is accelerating upwards, and will be less than his actual weight when the lift is decelerating or moving downwards.
The net force acting on the man can be calculated using Newton's second law of motion:
Net force (F) = ma, where m is the mass of the man and a is the acceleration of the lift.
The total force acting on the man is the sum of his actual weight and the net force:
Total force (T) = Weight of man (W) + Net force (F)
The reading on the weighing scale will be equal to the total force acting on the man.
Calculation:
Weight of man (W) = 70 kg × 10 m/s² = 700 N
Net force (F) = ma = 70 kg × 5 m/s² = 350 N
Total force (T) = W + F = 700 N + 350 N = 1050 N
Therefore, the reading on the weighing scale will be 1050 N.
Answer: a) 1050 N
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A man weighs 70 kg. He stands on a weighing scale in a lift which is moving upwards with an acceleration of 5ms2.What would be the reading on the scale? (g=10 ms2)a)1050 Nb)1200 Nc)220 Nd)1000 NCorrect answer is option 'A'. Can you explain this answer?
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A man weighs 70 kg. He stands on a weighing scale in a lift which is moving upwards with an acceleration of 5ms2.What would be the reading on the scale? (g=10 ms2)a)1050 Nb)1200 Nc)220 Nd)1000 NCorrect answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A man weighs 70 kg. He stands on a weighing scale in a lift which is moving upwards with an acceleration of 5ms2.What would be the reading on the scale? (g=10 ms2)a)1050 Nb)1200 Nc)220 Nd)1000 NCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A man weighs 70 kg. He stands on a weighing scale in a lift which is moving upwards with an acceleration of 5ms2.What would be the reading on the scale? (g=10 ms2)a)1050 Nb)1200 Nc)220 Nd)1000 NCorrect answer is option 'A'. Can you explain this answer?.
A man weighs 70 kg. He stands on a weighing scale in a lift which is moving upwards with an acceleration of 5ms2.What would be the reading on the scale? (g=10 ms2)a)1050 Nb)1200 Nc)220 Nd)1000 NCorrect answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A man weighs 70 kg. He stands on a weighing scale in a lift which is moving upwards with an acceleration of 5ms2.What would be the reading on the scale? (g=10 ms2)a)1050 Nb)1200 Nc)220 Nd)1000 NCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A man weighs 70 kg. He stands on a weighing scale in a lift which is moving upwards with an acceleration of 5ms2.What would be the reading on the scale? (g=10 ms2)a)1050 Nb)1200 Nc)220 Nd)1000 NCorrect answer is option 'A'. Can you explain this answer?.
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A man weighs 70 kg. He stands on a weighing scale in a lift which is moving upwards with an acceleration of 5ms2.What would be the reading on the scale? (g=10 ms2)a)1050 Nb)1200 Nc)220 Nd)1000 NCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A man weighs 70 kg. He stands on a weighing scale in a lift which is moving upwards with an acceleration of 5ms2.What would be the reading on the scale? (g=10 ms2)a)1050 Nb)1200 Nc)220 Nd)1000 NCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A man weighs 70 kg. He stands on a weighing scale in a lift which is moving upwards with an acceleration of 5ms2.What would be the reading on the scale? (g=10 ms2)a)1050 Nb)1200 Nc)220 Nd)1000 NCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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