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CO(g)is dissolved in H2Oat 25°C and 0.010 atm. Henry’s law constant for this system is 5.80 x104 atm. Thus, mole fraction of CO(g)is
- a)1.72 x 10-7
- b)8.28 x 10-7
- c)0.99
- d)0.01
Correct answer is option 'A'. Can you explain this answer?
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CO(g)is dissolved in H2Oat 25°C and 0.010 atm. Henry’s law ...
The mole fraction of a gas in solution is related to partial pressure of the gas above the solution by Henry’s law.
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CO(g)is dissolved in H2Oat 25°C and 0.010 atm. Henry’s law ...
Henry's Law:
- States that the amount of gas dissolved in a liquid is directly proportional to the partial pressure of the gas above the liquid.
- Mathematically it can be represented as P = kH x mole fraction, where P is the partial pressure of the gas, kH is the Henry's Law constant, and mole fraction is the ratio of moles of the gas to the total moles of the gas and liquid.
Given information:
- CO(g) is dissolved in H2O at 25°C and 0.010 atm.
- Henry's Law constant for this system is 5.80 x 10^4 atm.
To find: Mole fraction of CO(g)
Solution:
Using Henry's law equation, we can write:
P = kH x mole fraction
Here, P = 0.010 atm and kH = 5.80 x 10^4 atm.
Substituting these values, we get:
0.010 atm = (5.80 x 10^4 atm) x mole fraction
Solving for mole fraction, we get:
Mole fraction = 0.010 / (5.80 x 10^4) = 1.72 x 10^-7
Therefore, the mole fraction of CO(g) is 1.72 x 10^-7.
Hence, option A is the correct answer.
- States that the amount of gas dissolved in a liquid is directly proportional to the partial pressure of the gas above the liquid.
- Mathematically it can be represented as P = kH x mole fraction, where P is the partial pressure of the gas, kH is the Henry's Law constant, and mole fraction is the ratio of moles of the gas to the total moles of the gas and liquid.
Given information:
- CO(g) is dissolved in H2O at 25°C and 0.010 atm.
- Henry's Law constant for this system is 5.80 x 10^4 atm.
To find: Mole fraction of CO(g)
Solution:
Using Henry's law equation, we can write:
P = kH x mole fraction
Here, P = 0.010 atm and kH = 5.80 x 10^4 atm.
Substituting these values, we get:
0.010 atm = (5.80 x 10^4 atm) x mole fraction
Solving for mole fraction, we get:
Mole fraction = 0.010 / (5.80 x 10^4) = 1.72 x 10^-7
Therefore, the mole fraction of CO(g) is 1.72 x 10^-7.
Hence, option A is the correct answer.
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CO(g)is dissolved in H2Oat 25°C and 0.010 atm. Henry’s law constant for this system is 5.80 x104 atm. Thus, mole fraction of CO(g)isa)1.72 x 10-7b)8.28 x 10-7c)0.99d)0.01Correct answer is option 'A'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about CO(g)is dissolved in H2Oat 25°C and 0.010 atm. Henry’s law constant for this system is 5.80 x104 atm. Thus, mole fraction of CO(g)isa)1.72 x 10-7b)8.28 x 10-7c)0.99d)0.01Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for CO(g)is dissolved in H2Oat 25°C and 0.010 atm. Henry’s law constant for this system is 5.80 x104 atm. Thus, mole fraction of CO(g)isa)1.72 x 10-7b)8.28 x 10-7c)0.99d)0.01Correct answer is option 'A'. Can you explain this answer?.
CO(g)is dissolved in H2Oat 25°C and 0.010 atm. Henry’s law constant for this system is 5.80 x104 atm. Thus, mole fraction of CO(g)isa)1.72 x 10-7b)8.28 x 10-7c)0.99d)0.01Correct answer is option 'A'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about CO(g)is dissolved in H2Oat 25°C and 0.010 atm. Henry’s law constant for this system is 5.80 x104 atm. Thus, mole fraction of CO(g)isa)1.72 x 10-7b)8.28 x 10-7c)0.99d)0.01Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for CO(g)is dissolved in H2Oat 25°C and 0.010 atm. Henry’s law constant for this system is 5.80 x104 atm. Thus, mole fraction of CO(g)isa)1.72 x 10-7b)8.28 x 10-7c)0.99d)0.01Correct answer is option 'A'. Can you explain this answer?.
Solutions for CO(g)is dissolved in H2Oat 25°C and 0.010 atm. Henry’s law constant for this system is 5.80 x104 atm. Thus, mole fraction of CO(g)isa)1.72 x 10-7b)8.28 x 10-7c)0.99d)0.01Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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