4. If a car covers 2/5th of the total distance with V1 speed and 3/5th distance with V2 then average speed is ?Ans) 5V1V2/3V1+2V2?

Question

Answer

Call the total distance D and the total time T.

(2/5)D is covered at speed v1. The time taken is t1 = distance/speed = (2/5)D/v1

(3/5)D is covered at speed v2. The time taken is t2 = distance/speed = (3/5)D/v2

The total time T is:

T = t1 + t2

= (2/5)D/v1 + (3/5)D/v2

= (D/5)(2/v1 + 3/v2)

= (D/5)(2v2 + 3v1) / (v1v2)

Average speed = D/T = D / [ (D/5)(2v2 + 3v1) / (v1v2) ]

= 5v1v2 / (2v2 + 3v1)

Answer

Let's Calculate first total distance = 2/ 5 D + 3/ 5 D= 5 /5 D= DTotal time = T = t1 + t2 =( 2/5 D) / V1 +( 3/5 D) / V2 Let's put these values in equation of average speed Average speed = Total distance / Total time= D / [ ( 2/5 D) / V1 +( 3/5 D) / V2 ]= D / D/ 5 * [ 2/ V1 + 3 / V2 ] = 5 / [ 2 *V2 + 3 * V1 / V1 * V2 ] = 5 * V1 V2 / 3V1 + 2V2 IS THE ANSWER.....💯💯

Answer

The average speed of a car can be calculated by considering the distances covered at different speeds. In this case, the car covers 2/5th of the total distance with V1 speed and 3/5th of the distance with V2 speed. To find the average speed, we can use the formula:

Average speed = Total distance / Total time

Let's break down the problem and calculate the average speed step by step.

Step 1: Finding the distances covered
Let D be the total distance covered by the car.

The distance covered at V1 speed is given by:
Distance1 = (2/5) * D

The distance covered at V2 speed is given by:
Distance2 = (3/5) * D

Step 2: Finding the times taken
To calculate the average speed, we need to find the total time taken.

The time taken to cover Distance1 at V1 speed is given by:
Time1 = Distance1 / V1
Time1 = [(2/5) * D] / V1

The time taken to cover Distance2 at V2 speed is given by:
Time2 = Distance2 / V2
Time2 = [(3/5) * D] / V2

Step 3: Calculating the average speed
Now, we can calculate the average speed using the formula mentioned earlier.

Average speed = Total distance / Total time
Average speed = D / (Time1 + Time2)

Substituting the values of Time1 and Time2, we get:
Average speed = D / ([(2/5) * D] / V1 + [(3/5) * D] / V2)
Average speed = D / (2D/5V1 + 3D/5V2)
Average speed = D / (2D/5V1 + 3D/5V2) * (5V1V2/5V1V2)
Average speed = D * 5V1V2 / (2DV2 + 3DV1)
Average speed = 5V1V2 / (2V2 + 3V1)

Therefore, the average speed of the car is 5V1V2 / (2V2 + 3V1).

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