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In any g.p. the last term is 512 and the common ratio is 2,then 5th term is?
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In any g.p. the last term is 512 and the common ratio is 2,then 5th te...
According to me....2,4,8,16,32,64,128,256,512... is the g.p series...which has common ratio aas 2..and last term is 512...then 5th term is 32....HOPE U GOT IT...
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In any g.p. the last term is 512 and the common ratio is 2,then 5th te...
Given:

  • Last term (n) = 512

  • Common ratio (r) = 2



To find:

  • Fifth term of the GP



Solution:

  1. Using the formula for the nth term of a GP:


    • an = a1 * rn-1


  2. Substituting the given values in the formula:


    • 512 = a1 * 2n-1


  3. As we do not know the value of a1, we need to find it using another formula:


    • an = a1 * rn-1

    • a5 = a1 * 25-1

    • a5 = a1 * 24


  4. Substituting the value of an from step 2:


    • a5 = (512/16) * 24

    • a5 = 32 * 24

    • a5 = 32 * 16

    • a5 = 512


  5. Therefore, the fifth term of the GP is 512.

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In any g.p. the last term is 512 and the common ratio is 2,then 5th term is?
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