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 Which one of the following is the weakest base in gaseous phase?
  • a)
    Triethyl amine
  • b)
    Ethyl amine
  • c)
    Diethyl amine
  • d)
    Ammonia
Correct answer is option 'D'. Can you explain this answer?
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Which one of the following is the weakest base in gaseous phase?a)Trie...
 
As the number of alkyl group increases, due to +I effect the basicity of amines increases.
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Which one of the following is the weakest base in gaseous phase?a)Trie...
As the number of alkyl group increases, due to +I effect the basicity of amines increases.
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Which one of the following is the weakest base in gaseous phase?a)Trie...
Understanding Basicity in Gaseous Phase
When discussing the basicity of amines in the gaseous phase, we are often interested in how readily they can accept protons (H+). The strength of a base is largely influenced by its structure and the availability of the lone pair of electrons on the nitrogen atom.
Factors Influencing Basicity
- Electron-donating Groups: Alkyl groups are electron-donating, which increases the electron density on the nitrogen atom, enhancing basicity.
- Steric Hindrance: Larger alkyl groups can create steric hindrance, making it harder for the nitrogen to interact with protons.
- Hybridization: The hybridization state of the nitrogen atom can also impact its ability to donate its lone pair.
Comparison of the Given Amines
- Triethyl Amine: Has three ethyl groups which provide significant electron-donating effects, making it a strong base.
- Diethyl Amine: With two ethyl groups, it is still a strong base but less so than triethyl amine due to increased steric hindrance.
- Ethyl Amine: Contains one ethyl group, making it a weaker base compared to diethyl and triethyl amines, yet stronger than ammonia.
- Ammonia: Lacks any alkyl groups, which diminishes its ability to stabilize the positive charge that forms when it accepts a proton.
Conclusion
Among the options provided, ammonia is the weakest base in the gaseous phase due to its lack of electron-donating alkyl groups and minimal steric hindrance. Its lone pair is less available for protonation compared to the other amines, making it a less effective base overall. Therefore, the correct answer is option 'D' (Ammonia).
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