Alphabet series pairs before ‘ :: ‘ have a logic in some w...
Understanding the Pattern
To solve the problem, we need to analyze the relationship between the pairs of letters before the "::".
First Pair: ACE : FHJ
- A is the 1st letter of the alphabet.
- C is the 3rd letter.
- E is the 5th letter.
The letters F, H, and J can be derived as follows:
- F is the 6th letter (1 + 5).
- H is the 8th letter (3 + 5).
- J is the 10th letter (5 + 5).
Thus, each letter in the first group (ACE) is increased by 5 to get the corresponding letter in the second group (FHJ).
Second Pair: LNP : ?
Now, we need to apply the same logic to the second pair:
- L is the 12th letter.
- N is the 14th letter.
- P is the 16th letter.
We will add 5 to each of these:
- L (12) + 5 = 17, which corresponds to Q.
- N (14) + 5 = 19, which corresponds to S.
- P (16) + 5 = 21, which corresponds to U.
So, the resulting letters from LNP after applying the same logic are QSU.
Conclusion
Therefore, the missing set of alphabets after "::" is:
QSU
Thus, the correct answer is option C.
Alphabet series pairs before ‘ :: ‘ have a logic in some w...
The pattern involves skipping a set of letters between each group.
- The sequence ACE skips a letter to form FHJ.
- Each letter in ACE is followed by two skipped letters:
- A skips B to become C, then skips D to become E.
- F skips G to become H, then skips I to become J.
- Similarly, LNP follows this pattern:
- L skips M to become N, then skips O to become P.
- The next sequence after skipping letters is QSU.