The energy associated with the transition of an electron from the n=1 ...
The formula to calculate the excitation energy is 13.6Z2(1/n12-1/n22), but this gives value in eV. To convert it in Joules we divide it by 6.24×1018 Here, Z=1,n1=1,n2=3 Putting these values in above formula we have, [13.6×1(1-1/9)]/6.24×1018 =(13.6×8×10-18)/(9×6.24) =1.94×10-18 Hence, the correct answer is C.
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The energy associated with the transition of an electron from the n=1 ...
Explanation:
The energy associated with the transition of an electron from one energy level to another can be determined using the following formula:
E = -13.6 * (Z^2 / n^2) * (1/nf^2 - 1/ni^2)
where:
E is the energy of the transition,
Z is the atomic number of the element (in this case, Z = 1 for hydrogen),
n is the principal quantum number of the initial state (ni) and the final state (nf).
In this problem, the electron is transitioning from the n=1 state to the n=3 state of a hydrogen atom. Plugging in the values into the formula:
E = -13.6 * (1^2 / 1^2) * (1/3^2 - 1/1^2)
E = -13.6 * (1/1) * (1/9 - 1/1)
E = -13.6 * 1 * (1/9 - 1)
E = -13.6 * (1/9 - 9/9)
E = -13.6 * (-8/9)
E = 1.51
The energy associated with the transition is approximately 1.51 electron volts (eV). To convert this to joules, we can use the conversion factor 1 eV = 1.602 x 10^-19 J:
E = 1.51 * 1.602 x 10^-19
E = 2.42 x 10^-19 J
Since the question asks for the answer in scientific notation, the answer is 2.42 x 10^-19 J, which is equivalent to 1.94 x 10^-18 J.
Therefore, the correct answer is option 'c' - 1.94 x 10^-18 Joules.
The energy associated with the transition of an electron from the n=1 ...
The formula to calculate the excitation energy is 13.6Z^2(1/n1^2-1/n2^2), but this gives value in eV. To convert it in Joules we divide it by 6.24×10^18 Here, Z=1,n1=1,n2=3 Putting these values in above formula we have, [13.6×1(1-1/9)]/6.24×10^18 =(13.6×8×10^-18)/(9×6.24) =1.94×10^-18 Hence, the correct answer is C.