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In a class of 50 students, 35 opted for Mathematics and 37 opted for Commerce. The number of such students who opted for both Mathematics and Commerce are:
  • a)
    13
  • b)
    15
  • c)
    22
  • d)
    28
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In a class of 50 students, 35 opted for Mathematics and 37 opted for C...
Solution:

Given,

Total number of students = 50

Number of students opted for Mathematics = 35

Number of students opted for Commerce = 37

To find:

The number of students who opted for both Mathematics and Commerce

Let us assume the number of students who opted for both Mathematics and Commerce as x.

Now, using the formula of the total number of students in two sets, we can find the number of students who opted for Mathematics or Commerce or both.

Total number of students in Mathematics or Commerce = Number of students in Mathematics + Number of students in Commerce - Number of students who opted for both Mathematics and Commerce

50 = 35 + 37 - x

x = 22

Therefore, the number of students who opted for both Mathematics and Commerce is 22.
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Community Answer
In a class of 50 students, 35 opted for Mathematics and 37 opted for C...
Total =number of students chosen maths +no. of students chosen commerce -(intersection of both). 50 = 35+ 37 -(intersection of both). intersection of both=72-50 =22
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In a class of 50 students, 35 opted for Mathematics and 37 opted for Commerce. The number of such students who opted for both Mathematics and Commerce are:a)13b)15c)22d)28Correct answer is option 'C'. Can you explain this answer?
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