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The compound which exhibits Jahn-Teller distortion is:

  • a)
    [Co(H2​O)6​]6+

  • b)
    [Cu(H2O)6]2+

  • c)
    [Mn(H2O)6]2+

  • d)
    [Cr(H2​O)6]3+

Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The compound which exhibits Jahn-Teller distortion is:a)[Co(H2O)6]6+b)...
John teller distortion occur only in those compound in which unsymmetrical filling of t2g and eg orbital takes place ..I1st compound had d5 configuration n are symmetrically filled so no jtd.2nd has d4 configuration n high spin complex so its one eg orbital is unsymetrically filled resulting jtd
Option c has d3 configuration and as H20 is weak field ligand so its t2g orbital is symmetrically filled resultin no jtd
Last one has d6 configuration is low spin complex of iron due to strong field nature of pi acceptor ligand cNSo its teg orbital is symmetrically filled reasulting no jtdSo only option 2nd is correct
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The compound which exhibits Jahn-Teller distortion is:a)[Co(H2O)6]6+b)...
Jahn-Teller distortion is a phenomenon in which a molecule or an ion with an odd number of electrons in the degenerate orbitals undergoes a spontaneous distortion to lower its energy. This distortion occurs due to the repulsion between the electrons in the degenerate orbitals.

Among the given compounds, [Mn(H2O)6]3+ is the only compound that exhibits Jahn-Teller distortion. This is because Mn(III) ion has five d electrons, and these electrons occupy the degenerate d-orbitals. The presence of these electrons in the degenerate orbitals causes an instability in the molecule, and it undergoes a spontaneous distortion to lower its energy.

Explanation:

Let us consider the structure of [Mn(H2O)6]3+ ion. It is an octahedral complex with six water molecules surrounding the Mn(III) ion. The six water molecules occupy the six coordination sites of the octahedral geometry, and the Mn(III) ion is at the center of the octahedron.

The five d electrons of Mn(III) ion occupy the d-orbitals that are degenerate in the absence of any ligand field. In the presence of the six water molecules, these degenerate d-orbitals split into two sets of orbitals: a lower set of orbitals (t2g) and an upper set of orbitals (eg).

In the case of [Mn(H2O)6]3+ ion, the t2g set of orbitals is completely filled with electrons, while the eg set of orbitals is half-filled with electrons. This electronic configuration is known as the Hund's rule configuration.

Now, due to the repulsion between the electrons in the eg set of orbitals, the molecule undergoes a spontaneous distortion to lower its energy. This distortion can occur in two ways:

1. Jahn-Teller elongation: In this case, the molecule elongates along the axis perpendicular to the eg set of orbitals. This elongation causes the two degenerate eg orbitals to split further apart, reducing the electron-electron repulsion.

2. Jahn-Teller compression: In this case, the molecule compresses along the axis parallel to the eg set of orbitals. This compression causes the two degenerate eg orbitals to come closer, reducing the electron-electron repulsion.

In the case of [Mn(H2O)6]3+ ion, the distortion that occurs is Jahn-Teller elongation. This elongation causes the two water molecules along the axis perpendicular to the eg set of orbitals to move away from the Mn(III) ion, while the other four water molecules remain in their original positions. This distortion lowers the energy of the molecule and stabilizes it.

Therefore, [Mn(H2O)6]3+ is the only compound among the given options that exhibits Jahn-Teller distortion.
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