How many ways can three white and three red balloons be arranged in a ...
3 white balls, 3 red balls
Total balls = 6
Total no. of ways = (6!)/(3!)(3!)
= (6*5*4*3!)/(3!*3*2)
= (5*4) = 20
How many ways can three white and three red balloons be arranged in a ...
Arranging Three White and Three Red Balloons in a Row
To determine the number of ways in which three white and three red balloons can be arranged in a row, we can use the formula for permutations of objects with repetition.
Formula: n! / (n1!n2!...nk!), where n is the total number of objects, and n1, n2,...nk are the number of objects of each type.
Using this formula, we can calculate the number of arrangements as follows:
n = 6 (total number of balloons)
n1 = 3 (number of white balloons)
n2 = 3 (number of red balloons)
Number of arrangements = 6! / (3! 3!) = 20
Therefore, there are 20 ways in which three white and three red balloons can be arranged in a row.
Explanation:
- The formula for permutations with repetition is n! / (n1!n2!...nk!), where n is the total number of objects, and n1, n2,...nk are the number of objects of each type.
- In this case, we have a total of six balloons, with three white and three red balloons.
- Using the formula, we can calculate the number of arrangements as 6! / (3! 3!) = 20.
- This means that there are 20 ways in which we can arrange the three white and three red balloons in a row.
- Therefore, the correct answer is option C.