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One gram sample of NH4NO3 is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by 6.12 K. The heat capacity of the system is 1.23 kJ/g/deg. What is the molar heat of decomposition for NH4NO3?
- a)–7.53 KJ mol–1
- b)–398.1 KJ mol–1
- c)–16.1 KJ mol–1
- d)602 KJ mol
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
One gram sample of NH4NO3is decomposed in a bomb calorimeter. The temp...
The heat change is given by q = C x ∆T = 1.23 x 6.12 = 7.53 kJ. As the reaction is
exothermic, the heat of decomposition for 1.00 g of NH4NO3 is ∆H = -7.53 kJ.
The molar mass of NH4NO3 is:
molar mass = (2 x 14.01 (N)) + (4 x 1.008 (H)) + (3 x 16.00 (O)) = 80.052
1.000 g therefore corresponds to 1.000/80.052 = 0.0125 mol. The molar heat of
decomposition is then: ∆H = -7.53/0.0125 = -602kJ mol-1
Most Upvoted Answer
One gram sample of NH4NO3is decomposed in a bomb calorimeter. The temp...
To find the molar heat of decomposition for NH4NO3, we can use the equation:
q = m * C * ΔT
Where:
q = heat absorbed or released
m = mass of the substance (in grams)
C = heat capacity of the system (in kJ/g/°C)
ΔT = change in temperature (in °C)
We are given:
Mass of NH4NO3 = 1 gram
Change in temperature = 6.12 K
Heat capacity = 1.23 kJ/g/°C
First, we need to convert the mass of NH4NO3 to moles. The molar mass of NH4NO3 is calculated as follows:
NH4NO3 = (1 x 14.01) + (4 x 1.01) + (1 x 14.01) + (3 x 16.00) = 80.04 g/mol
Using the equation:
moles = mass / molar mass
moles of NH4NO3 = 1 g / 80.04 g/mol = 0.0125 mol
Now, we can calculate the heat absorbed or released (q) using the equation:
q = m * C * ΔT
q = (0.0125 mol) * (1.23 kJ/g/°C) * (6.12 K)
q = 0.092 kJ
Finally, to find the molar heat of decomposition, we divide the heat absorbed or released by the number of moles:
Molar heat of decomposition = q / moles
Molar heat of decomposition = 0.092 kJ / 0.0125 mol
Molar heat of decomposition = 7.36 kJ/mol
Since the question asks for the answer in KJ/mol, we can round the value to 7.4 KJ/mol. However, none of the given options match this value.
Therefore, the correct answer is not provided in the given options.
q = m * C * ΔT
Where:
q = heat absorbed or released
m = mass of the substance (in grams)
C = heat capacity of the system (in kJ/g/°C)
ΔT = change in temperature (in °C)
We are given:
Mass of NH4NO3 = 1 gram
Change in temperature = 6.12 K
Heat capacity = 1.23 kJ/g/°C
First, we need to convert the mass of NH4NO3 to moles. The molar mass of NH4NO3 is calculated as follows:
NH4NO3 = (1 x 14.01) + (4 x 1.01) + (1 x 14.01) + (3 x 16.00) = 80.04 g/mol
Using the equation:
moles = mass / molar mass
moles of NH4NO3 = 1 g / 80.04 g/mol = 0.0125 mol
Now, we can calculate the heat absorbed or released (q) using the equation:
q = m * C * ΔT
q = (0.0125 mol) * (1.23 kJ/g/°C) * (6.12 K)
q = 0.092 kJ
Finally, to find the molar heat of decomposition, we divide the heat absorbed or released by the number of moles:
Molar heat of decomposition = q / moles
Molar heat of decomposition = 0.092 kJ / 0.0125 mol
Molar heat of decomposition = 7.36 kJ/mol
Since the question asks for the answer in KJ/mol, we can round the value to 7.4 KJ/mol. However, none of the given options match this value.
Therefore, the correct answer is not provided in the given options.
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One gram sample of NH4NO3is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by 6.12 K. The heat capacity of the system is 1.23 kJ/g/deg. What is the molar heat of decomposition for NH4NO3?a)–7.53 KJ mol–1b)–398.1 KJ mol–1c)–16.1 KJ mol–1d)602 KJ molCorrect answer is option 'D'. Can you explain this answer?
Question Description
One gram sample of NH4NO3is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by 6.12 K. The heat capacity of the system is 1.23 kJ/g/deg. What is the molar heat of decomposition for NH4NO3?a)–7.53 KJ mol–1b)–398.1 KJ mol–1c)–16.1 KJ mol–1d)602 KJ molCorrect answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about One gram sample of NH4NO3is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by 6.12 K. The heat capacity of the system is 1.23 kJ/g/deg. What is the molar heat of decomposition for NH4NO3?a)–7.53 KJ mol–1b)–398.1 KJ mol–1c)–16.1 KJ mol–1d)602 KJ molCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One gram sample of NH4NO3is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by 6.12 K. The heat capacity of the system is 1.23 kJ/g/deg. What is the molar heat of decomposition for NH4NO3?a)–7.53 KJ mol–1b)–398.1 KJ mol–1c)–16.1 KJ mol–1d)602 KJ molCorrect answer is option 'D'. Can you explain this answer?.
One gram sample of NH4NO3is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by 6.12 K. The heat capacity of the system is 1.23 kJ/g/deg. What is the molar heat of decomposition for NH4NO3?a)–7.53 KJ mol–1b)–398.1 KJ mol–1c)–16.1 KJ mol–1d)602 KJ molCorrect answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about One gram sample of NH4NO3is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by 6.12 K. The heat capacity of the system is 1.23 kJ/g/deg. What is the molar heat of decomposition for NH4NO3?a)–7.53 KJ mol–1b)–398.1 KJ mol–1c)–16.1 KJ mol–1d)602 KJ molCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One gram sample of NH4NO3is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by 6.12 K. The heat capacity of the system is 1.23 kJ/g/deg. What is the molar heat of decomposition for NH4NO3?a)–7.53 KJ mol–1b)–398.1 KJ mol–1c)–16.1 KJ mol–1d)602 KJ molCorrect answer is option 'D'. Can you explain this answer?.
Solutions for One gram sample of NH4NO3is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by 6.12 K. The heat capacity of the system is 1.23 kJ/g/deg. What is the molar heat of decomposition for NH4NO3?a)–7.53 KJ mol–1b)–398.1 KJ mol–1c)–16.1 KJ mol–1d)602 KJ molCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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One gram sample of NH4NO3is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by 6.12 K. The heat capacity of the system is 1.23 kJ/g/deg. What is the molar heat of decomposition for NH4NO3?a)–7.53 KJ mol–1b)–398.1 KJ mol–1c)–16.1 KJ mol–1d)602 KJ molCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for One gram sample of NH4NO3is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by 6.12 K. The heat capacity of the system is 1.23 kJ/g/deg. What is the molar heat of decomposition for NH4NO3?a)–7.53 KJ mol–1b)–398.1 KJ mol–1c)–16.1 KJ mol–1d)602 KJ molCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of One gram sample of NH4NO3is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by 6.12 K. The heat capacity of the system is 1.23 kJ/g/deg. What is the molar heat of decomposition for NH4NO3?a)–7.53 KJ mol–1b)–398.1 KJ mol–1c)–16.1 KJ mol–1d)602 KJ molCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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