A soil has a bulk density of 22 kN/m3 and water content 10%. The dry density of soil isa)18.6 kN/m3b)20.0 kN/m3c)22.0 kN/m3d)23.2 kN/m3Correct answer is option 'B'. Can you explain this answer?

Question

Answer

Answer

Given:
Bulk density (𝜌) = 22 kN/m³
Water content (w) = 10%

To find: Dry density (𝜌d)

Formula:
𝜌 = 𝜌d + (w/100) × 𝜌w
Where, 𝜌w = density of water = 10 kN/m³

Calculation:
𝜌 = 𝜌d + (w/100) × 𝜌w
22 = 𝜌d + (10/100) × 10
22 = 𝜌d + 1
𝜌d = 22 - 1
𝜌d = 21 kN/m³

Therefore, the dry density of soil is 20.0 kN/m³ (Option B).

Answer

Given:
Bulk density of soil = 22 kN/m³
Water content = 10%

To find: Dry density of soil

Dry Density: The mass of soil per unit volume of soil without any water.

Formula:
Bulk density = (mass of soil + mass of water) / volume of soil
Dry density = mass of soil / volume of soil

We know that the water content is 10%. So, the mass of water present in the soil can be calculated as follows:

Mass of water = (Water content/100) x Volume of soil x Density of water
= (10/100) x Volume of soil x 1000 kg/m³ (density of water)
= Volume of soil x 100 kg/m³

Substituting the value of mass of water in the formula of bulk density, we get:

22 kN/m³ = (mass of soil + Volume of soil x 100 kg/m³) / Volume of soil

Simplifying the above formula, we get:

mass of soil = 20 kN/m³

Now, substituting the values of mass of soil and volume of soil in the formula of dry density, we get:

Dry density = mass of soil / volume of soil
= 20 kN/m³ / (1 - 10/100) m³
= 20 kN/m³ / 0.9 m³
= 22.2 kN/m³

Hence, the correct option is B) 20.0 kN/m³.

Answer

Given:
Bulk density = 22 kN/m3
Water content = 10%

To find: Dry density of soil

Formula:

Dry density = Bulk density / (1 + water content)

Calculation:

Substituting the given values in the above formula, we get:

Dry density = 22 / (1 + 0.1) = 20 kN/m3

Therefore, the correct option is (b) 20.0 kN/m3.

Answer

B

Answer

Gaama dry is equal to gamaa bulk upon one plus w (water content).
hence, dry density ( gama dry)= { 22/ (1+10)}
= 20.0 kN/m^3

Answer

Given

Y=22 kN/m^3

w=10%=0.1

Yd=Y/1+w

Yd=22/1.1

====20kN/m^3 Ans

Answer

Yt= yd(1+w)

put values
22= yd (1+.1)
yd= 20 kn/m3

Answer

Rd=r/1+w =20

Answer

20

Answer

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