If water content available is 22 % and the specific gravity of the sol...
Calculation of Void Ratio
Given parameters:
- Water content = 22%
- Specific gravity of solid = 2.82
- Unit weight of water = 9.81 kN/m³
- Bulk density = 18.5 kN/m³
First, we need to calculate the dry density of the soil. We can do this by using the following formula:
Dry Density = Bulk Density / (1 + Water Content)
Substituting the values, we get:
Dry Density = 18.5 / (1 + 0.22) = 15.04 kN/m³
Next, we need to calculate the unit weight of solids:
Unit Weight of Solids = Specific Gravity x Unit Weight of Water
Substituting the values, we get:
Unit Weight of Solids = 2.82 x 9.81 = 27.83 kN/m³
Finally, we can calculate the void ratio using the following formula:
Void Ratio = (Unit Weight of Solids - Dry Density) / Dry Density
Substituting the values, we get:
Void Ratio = (27.83 - 15.04) / 15.04 = 0.851
Therefore, the void ratio of the soil sample is 0.851.
Explanation
Water content, specific gravity of solid, unit weight of water, and bulk density are all important parameters in soil mechanics. The water content represents the amount of water present in the soil sample, while the specific gravity of solid represents the density of the solid particles in the soil. The unit weight of water is a constant value, and the bulk density represents the total density of the soil sample including both solids and voids.
The dry density of the soil is calculated by subtracting the weight of water from the bulk density, which gives us the weight of solids present in the soil sample. The unit weight of solids is then calculated using the specific gravity of solid and the unit weight of water. Finally, the void ratio is calculated by comparing the weight of solids to the total volume of the soil sample, which includes both the solids and the voids.
The void ratio is an important parameter in soil mechanics as it represents the amount of voids present in the soil sample. It is a key factor in determining the compressibility and shear strength of soil.
If water content available is 22 % and the specific gravity of the sol...
Bulk Density= ((G+S*e)/(1+e))*(Unit weight of water)
Since S*e = w*G = 0.22*2.82 = 0.6204
Upon substitution
18.5 = ((2.82+0.6204)/(1+e))*9.81
(1+e) = 1.819
--> e = 0.819 or 81.9%
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