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The general solution of sin = 0 is
- a)nπ where n is a real number
- b)nπ, where n is an integer
- c)2π
- d)π
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The general solution of sin = 0 isa)nπ where n is a real numberb)...
sinθ = 0
⇒ sin-1 θ = 0,π,2π,...
⇒ θ = 0 + nπ → n∈Z
The general solution for sin x = 0 will be, x = nπ, where n∈I.
⇒ sin-1 θ = 0,π,2π,...
⇒ θ = 0 + nπ → n∈Z
The general solution for sin x = 0 will be, x = nπ, where n∈I.
Most Upvoted Answer
The general solution of sin = 0 isa)nπ where n is a real numberb)...
Solution:
General Solution of sin = 0
The general solution of sin = 0 is given by the equation:
sin θ = 0
where θ is the angle in radians.
To find the general solution of this equation, we need to find all the values of θ that satisfy the equation.
Step 1: Find the First Solution
The first solution of the equation sin θ = 0 is given by:
θ = 0
This is because the sine function is equal to zero at the angle of zero degrees.
Step 2: Find the Other Solutions
The other solutions of the equation sin θ = 0 can be found by adding or subtracting multiples of π radians to the first solution.
That is,
θ = 0 + nπ
where n is an integer.
Hence, the general solution of sin θ = 0 is given by:
θ = nπ, where n is an integer.
Option B is the correct answer because the general solution of the equation sin θ = 0 is a set of values that are integers.
General Solution of sin = 0
The general solution of sin = 0 is given by the equation:
sin θ = 0
where θ is the angle in radians.
To find the general solution of this equation, we need to find all the values of θ that satisfy the equation.
Step 1: Find the First Solution
The first solution of the equation sin θ = 0 is given by:
θ = 0
This is because the sine function is equal to zero at the angle of zero degrees.
Step 2: Find the Other Solutions
The other solutions of the equation sin θ = 0 can be found by adding or subtracting multiples of π radians to the first solution.
That is,
θ = 0 + nπ
where n is an integer.
Hence, the general solution of sin θ = 0 is given by:
θ = nπ, where n is an integer.
Option B is the correct answer because the general solution of the equation sin θ = 0 is a set of values that are integers.
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Community Answer
The general solution of sin = 0 isa)nπ where n is a real numberb)...
Option B SinX=0 where X => 0, 180 , 360 , 540............and so on we can see that its a series of common difference of 180 degrees 180=π Therefore, we can say that if SinX=0 , Then X is the multiple of π Therefore, nπ ...(n is an integer) 0 = 0π 180 = π 360 = 2π .........and so onn
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The general solution of sin = 0 isa)nπ where n is a real numberb)nπ, where n is an integerc)2πd)πCorrect answer is option 'B'. Can you explain this answer?
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