If you have 2 moles of A and 3 moles of B, Identify the limiting reagent in the following reaction.A + B → ABa)Ab)Bc)A as well as Bd)NoneCorrect answer is option 'A'. Can you explain this answer?

Question

If you have 2 moles of A and 3 moles of B, Identify the limiting reagent in the following reaction.A + B &#8594; AB&#8203;a)Ab)Bc)A as well as Bd)NoneCorrect answer is option 'A'. Can you explain this answer?

Answer

A + B → AB divide given moles of each reactant by their stoichiometric coefficient , the one with least ratio is limit reagents divide with their co efficient A=2/1 =2 B=3/1 =3. So A is the limiting reagent.

Answer

Trick to solve limiting reagent problems easily

https://edurev.in/studytube/Trick-to-solve-limiting-reagent-problems-easily/d35a7874-143b-4973-843d-80ce23fb8973_v?courseId=-1

Answer

A + B --->AB divide given moles of each reactant by their stoichiometric coefficient , the one with least ratio is limit reagents divide with their co efficient A=2/1 =2 B=3/1 =3 so A is the limiting reagent

Answer

Limiting Reagent

The limiting reagent is the reactant that is completely consumed in a chemical reaction, thereby limiting the amount of product that can be formed. It determines the maximum amount of product that can be produced.

In this case, we have 2 moles of A and 3 moles of B. The balanced chemical equation for the reaction is:

A + B -> AB

To determine the limiting reagent, we need to compare the number of moles of each reactant with the stoichiometric ratio in the balanced equation.

Comparison

1. Moles of A: 2 moles
2. Moles of B: 3 moles

According to the balanced equation, the stoichiometric ratio between A and B is 1:1. This means that 1 mole of A reacts with 1 mole of B to form 1 mole of AB.

Calculating the Limiting Reagent

To calculate the limiting reagent, we compare the moles of each reactant with the stoichiometric ratio.

1. Moles of A: 2 moles
- This means that we have an excess of A, as we would only need 2 moles of B to react with the 2 moles of A.

2. Moles of B: 3 moles
- This means that B is the limiting reagent, as we would need 3 moles of A to react with the 3 moles of B.

Therefore, the limiting reagent in this reaction is B.

Explanation

Since we have more moles of B than A, it might seem counterintuitive that B is the limiting reagent. However, the stoichiometric ratio between A and B is 1:1. This means that for every mole of A, we need exactly 1 mole of B to react completely.

In this case, we have excess A, meaning that there will be leftover A after all the B has been consumed. The excess A will not be able to react further, as there is no more B available. Therefore, B is the limiting reagent, as it determines the maximum amount of AB that can be formed.

It is important to identify the limiting reagent in a reaction because it allows us to calculate the theoretical yield of the product.

Answer

A as well as B

Top Courses for Class 11View all

Mathematics (Maths) Class 11

Chemistry Class 11

English Snapshot Class 11

CUET Science Subjects Mock Tests 2026

English Class 11

Top Courses for Class 11

Top Courses for Class 11

Related Content

Schools

Competitive Examinations

Quick Access Links

Technical Exams