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 The solution of cos 4x = cos 2x
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'D'. Can you explain this answer?
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The solution of cos 4x = cos 2xa)b)c)d)Correct answer is option 'D'. C...
cos 4x = cos 2x
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The solution of cos 4x = cos 2xa)b)c)d)Correct answer is option 'D'. C...
Cos 4x=cos 2x = cos 4x -cos 2x =0 = -2sin (4x+2x/2) sin (4x-2x/2) =0 {cos x - cos y = -2sin (x+y/2)sin(x-y/2)} now = sin 3x sin x =0 = sin 3x=0 or sin x =0 = 3x = nπ or x = nπ, where n belongs to Z = x = nπ/3 or x = nπ, where n belongs to Z .... hope u understand
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The solution of cos 4x = cos 2xa)b)c)d)Correct answer is option 'D'. Can you explain this answer?
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