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A car A is going north-east at 80km/h and another car B is going south-east at 60km/h. The direction of the relative velocity of A with B makes an angle of x with north find tan x?
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A car A is going north-east at 80km/h and another car B is going south...
Given:

Car A is going north-east at 80 km/h

Car B is going south-east at 60 km/h

To find:

The direction of the relative velocity of car A with car B makes an angle x with north. Find tan x.

Solution:

Let us consider the two cars A and B as shown in the figure below:



The velocity of car A can be resolved into two components:

1. Velocity towards north = 80/sqrt(2) km/h (since it is moving at 45 degrees to the north direction)

2. Velocity towards east = 80/sqrt(2) km/h (since it is moving at 45 degrees to the east direction)

Similarly, the velocity of car B can be resolved into two components:

1. Velocity towards south = 60/sqrt(2) km/h (since it is moving at 45 degrees to the south direction)

2. Velocity towards east = 60/sqrt(2) km/h (since it is moving at 45 degrees to the east direction)

The relative velocity of car A with respect to car B can be found by subtracting the velocity of car B from the velocity of car A:

1. Velocity towards north-east = (80/sqrt(2) - 60/sqrt(2)) km/h = 20/sqrt(2) km/h

The direction of the relative velocity of car A with respect to car B makes an angle x with north. This angle can be found as follows:

tan x = (Velocity towards north-east) / (Velocity towards north)

tan x = (20/sqrt(2)) / (80/sqrt(2))

tan x = 1/4

tan x = 0.25

Therefore, the direction of the relative velocity of car A with respect to car B makes an angle of tan^-1(0.25) with north.
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A car A is going north-east at 80km/h and another car B is going south...
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A car A is going north-east at 80km/h and another car B is going south-east at 60km/h. The direction of the relative velocity of A with B makes an angle of x with north find tan x?
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