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A metallic wire of 40 Ω resistance is drawn to double its length. Its new resistance will be
- a)20 Ω
- b)80 Ω
- c)160 Ω
- d)320 Ω
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A metallic wire of 40 Ω resistance is drawn to double its length. Its ...
Calculating the new resistance of a metallic wire after being drawn to double its length.
Formula:
The resistance of a wire is directly proportional to its length and inversely proportional to its area of cross-section.
Explanation:
When a metallic wire is drawn to double its length, its area of cross-section decreases to half of its original value.
Thus, the new resistance can be calculated using the following formula:
New resistance = (Original resistance x New length^2) / (Original length^2 x New area of cross-section)
As the wire is drawn to double its length, the new length will be 2 times the original length.
The area of cross-section is inversely proportional to the square of the length, so the new area of cross-section will be half of its original value.
Therefore,
New resistance = (40 x 2^2) / (1 x 1/2)
New resistance = (40 x 4) / (1/2)
New resistance = 160 Ω
Hence, the correct answer is option 'C' (160 Ω).
Formula:
The resistance of a wire is directly proportional to its length and inversely proportional to its area of cross-section.
Explanation:
When a metallic wire is drawn to double its length, its area of cross-section decreases to half of its original value.
Thus, the new resistance can be calculated using the following formula:
New resistance = (Original resistance x New length^2) / (Original length^2 x New area of cross-section)
As the wire is drawn to double its length, the new length will be 2 times the original length.
The area of cross-section is inversely proportional to the square of the length, so the new area of cross-section will be half of its original value.
Therefore,
New resistance = (40 x 2^2) / (1 x 1/2)
New resistance = (40 x 4) / (1/2)
New resistance = 160 Ω
Hence, the correct answer is option 'C' (160 Ω).
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Community Answer
A metallic wire of 40 Ω resistance is drawn to double its length. Its ...
Resistance becomes n^2times when length is increased by n times as 2time increase in length produce 4 time in resistance as 40*4=160ohm u can prove this result by equating the volume of wire in both in form of area and lengt
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A metallic wire of 40 Ω resistance is drawn to double its length. Its new resistance will bea)20 Ωb)80 Ωc)160 Ωd)320 ΩCorrect answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A metallic wire of 40 Ω resistance is drawn to double its length. Its new resistance will bea)20 Ωb)80 Ωc)160 Ωd)320 ΩCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metallic wire of 40 Ω resistance is drawn to double its length. Its new resistance will bea)20 Ωb)80 Ωc)160 Ωd)320 ΩCorrect answer is option 'C'. Can you explain this answer?.
A metallic wire of 40 Ω resistance is drawn to double its length. Its new resistance will bea)20 Ωb)80 Ωc)160 Ωd)320 ΩCorrect answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A metallic wire of 40 Ω resistance is drawn to double its length. Its new resistance will bea)20 Ωb)80 Ωc)160 Ωd)320 ΩCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metallic wire of 40 Ω resistance is drawn to double its length. Its new resistance will bea)20 Ωb)80 Ωc)160 Ωd)320 ΩCorrect answer is option 'C'. Can you explain this answer?.
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