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a,b,c€R and '1' is a root of equation ax+ bx + c=0 then equation 4ax+ 3bx +2c=0 .c 0 has
  • a)
    Imaginary roots
  • b)
    real and equal roots
  • c)
    real and unequal roots
  • d)
    rational roots
Correct answer is option 'C'. Can you explain this answer?
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Imaginary roots always exist in conjugate so that option is removed now 1+y=-3b/4a ( y be the other root) so y=-(3b+4a)/4a now product of roots =2c/4a so on solving by putting the value of y you get 3b+4a+2c=0 from here 9b^2=(4a+2c)^2 now calculate determinant it comes 9b^2-32ac put the value of 9b^2 from above here you will get D=(4a-2c)^2 so D>0 so real and unequal roots
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a,b,c€R and '1' is a root of equation ax2+ bx + c=0 then equation 4ax2+ 3bx +2c=0 .c0 hasa)Imaginary rootsb)real and equal rootsc)real and unequal rootsd)rational rootsCorrect answer is option 'C'. Can you explain this answer?
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a,b,c€R and '1' is a root of equation ax2+ bx + c=0 then equation 4ax2+ 3bx +2c=0 .c0 hasa)Imaginary rootsb)real and equal rootsc)real and unequal rootsd)rational rootsCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about a,b,c€R and '1' is a root of equation ax2+ bx + c=0 then equation 4ax2+ 3bx +2c=0 .c0 hasa)Imaginary rootsb)real and equal rootsc)real and unequal rootsd)rational rootsCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for a,b,c€R and '1' is a root of equation ax2+ bx + c=0 then equation 4ax2+ 3bx +2c=0 .c0 hasa)Imaginary rootsb)real and equal rootsc)real and unequal rootsd)rational rootsCorrect answer is option 'C'. Can you explain this answer?.
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