Two beams of equal cross-sectional area are subjected to equal bending...
If D is diameter of circle and 'a' the side of square section,
Z for circular section

and Z for square section

View all questions of this test
Two beams of equal cross-sectional area are subjected to equal bending...
Explanation:
When a beam is subjected to bending moment, it experiences tensile stress on one face and compressive stress on the other face. The magnitude of these stresses depends on the cross-sectional area and shape of the beam.
Comparing Square and Circular Cross-Sections:
1. Square Cross-Section:
In a square cross-section, the maximum distance between the neutral axis and the extreme fiber is d/2, where d is the side of the square. Therefore, the tensile and compressive stresses at the extreme fiber are given by:
σ = M/(Z*d/2) = 2*M/(d^2)
2. Circular Cross-Section:
In a circular cross-section, the maximum distance between the neutral axis and the extreme fiber is d/2, where d is the diameter of the circle. Therefore, the tensile and compressive stresses at the extreme fiber are given by:
σ = M/(Z*d/4) = 4*M/(π*d^2)
Comparing the two equations, it can be observed that the stress in a circular section beam is greater than that in a square section beam. This means that for the same bending moment, a circular section beam will experience higher stresses than a square section beam.
Therefore, the circular section beam will be stronger than the square section beam.
Conclusion:
The strength of a beam depends on its cross-sectional area and shape. For the same bending moment, a circular section beam will be stronger than a square section beam because it experiences higher stresses.
Two beams of equal cross-sectional area are subjected to equal bending...
Square cross section beam will have more strength.
beacuase the distance between nutral axis and outer febric will be min. in square cross section beam.