Among lyman,balmer,paschen and brackett series in hydrogen atomic spectra which has higher energy?

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Answer

Higher energy among Lyman, Balmer, Paschen and Brackett series in hydrogen atomic spectra

When an electron in a hydrogen atom jumps from a higher energy level to a lower energy level, it releases energy in the form of electromagnetic radiation. This radiation consists of different wavelengths, which correspond to different spectral lines in the hydrogen atomic spectra. These spectral lines are grouped into different series, such as Lyman, Balmer, Paschen, and Brackett series, based on the final energy level of the electron.

Lyman series

The Lyman series corresponds to electron transitions from higher energy levels to the ground state (n=1). The spectral lines in this series are in the ultraviolet region of the electromagnetic spectrum. The first line in this series is the Lyman alpha line (121.6 nm).

Balmer series

The Balmer series corresponds to electron transitions from higher energy levels to the second energy level (n=2). The spectral lines in this series are in the visible region of the electromagnetic spectrum. The first line in this series is the H-alpha line (656.3 nm).

Paschen series

The Paschen series corresponds to electron transitions from higher energy levels to the third energy level (n=3). The spectral lines in this series are in the infrared region of the electromagnetic spectrum. The first line in this series is the Paschen alpha line (1.09 µm).

Brackett series

The Brackett series corresponds to electron transitions from higher energy levels to the fourth energy level (n=4). The spectral lines in this series are in the infrared region of the electromagnetic spectrum. The first line in this series is the Brackett alpha line (4.05 µm).

Higher energy

The energy of the spectral lines in the hydrogen atomic spectra is inversely proportional to the wavelength of the radiation. This means that the shorter the wavelength, the higher the energy. Therefore, the Lyman series, which has the shortest wavelengths in the ultraviolet region of the spectrum, has the highest energy among the four series. The Paschen and Brackett series, which have longer wavelengths in the infrared region of the spectrum, have lower energies. The Balmer series, which is in the visible region of the spectrum, has intermediate energies.

Therefore, the order of increasing energy among the four series in the hydrogen atomic spectra is:

Brackett series

Paschen series

Balmer series

Lyman series (highest energy)

Answer

If you take the limiting line then energy difference for lyman will be more so it will have more energy infact any line you take fix one principle quantum number suppose n so for lyman n》1 so more energy difference than rest all

Answer

Lyman series

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