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A resistive force of 16 N acts on a ball of mass 40 g continuously. If the initial velocity of the ball is 24 ms-1 ,the time taken by it to come to rest is:
- a)0.04 s
- b)0.08 s
- c)0.06 s
- d)0.02 s
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A resistive force of 16 N acts on a ball of mass 40 g continuously. If...
Mass of ball: m= 40 g = 0.040kg
resistive force: F = -16 N
thus resistive acceleration, a = F/m (because force, F= ma)
thus a = -400m/s^2
initial velocity, u = 24m/s
final velocity, v = 0m/s
Thus according to first equation of motion, v = u+at (t=timetaken)
t= 0.06s
Most Upvoted Answer
A resistive force of 16 N acts on a ball of mass 40 g continuously. If...
Mass of ball: m= 40 g = 0.040kg
resistive force: F = -16 N
thus resistive acceleration, a = F/m (because force, F= ma)
thus a = -400m/s2
initial velocity, u = 24m/s
final velocity, v = 0m/s
Thus according to first equation of motion, v = u+at (t=timetaken)
t= 0.06s
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A resistive force of 16 N acts on a ball of mass 40 g continuously. If...
Given:
Mass of the ball (m) = 40 g = 0.04 kg
Resistive force (F) = 16 N
Initial velocity (u) = 24 m/s
To find:
Time taken by the ball to come to rest (t)
We can use Newton's second law of motion to solve this problem. The second law states that the net force acting on an object is equal to the product of its mass and acceleration. In this case, since the ball is coming to rest, the net force is equal to the resistive force.
1. Calculate the acceleration:
Using Newton's second law, we have:
F = ma
Where F is the resistive force, m is the mass of the ball, and a is the acceleration.
Substituting the given values, we get:
16 = 0.04a
Solving for a, we get:
a = 16/0.04 = 400 m/s²
2. Calculate the time taken to come to rest:
We can use the equation of motion:
v = u + at
Where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken.
Since the final velocity is 0 m/s (as the ball comes to rest), we have:
0 = 24 + (400)t
Rearranging the equation, we get:
400t = -24
Dividing both sides by 400, we get:
t = -24/400 = -0.06 s
However, time cannot be negative in this context, so we take the magnitude of the time, which is 0.06 s. Therefore, the time taken by the ball to come to rest is 0.06 s.
Hence, the correct answer is option C) 0.06 s.
Mass of the ball (m) = 40 g = 0.04 kg
Resistive force (F) = 16 N
Initial velocity (u) = 24 m/s
To find:
Time taken by the ball to come to rest (t)
We can use Newton's second law of motion to solve this problem. The second law states that the net force acting on an object is equal to the product of its mass and acceleration. In this case, since the ball is coming to rest, the net force is equal to the resistive force.
1. Calculate the acceleration:
Using Newton's second law, we have:
F = ma
Where F is the resistive force, m is the mass of the ball, and a is the acceleration.
Substituting the given values, we get:
16 = 0.04a
Solving for a, we get:
a = 16/0.04 = 400 m/s²
2. Calculate the time taken to come to rest:
We can use the equation of motion:
v = u + at
Where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken.
Since the final velocity is 0 m/s (as the ball comes to rest), we have:
0 = 24 + (400)t
Rearranging the equation, we get:
400t = -24
Dividing both sides by 400, we get:
t = -24/400 = -0.06 s
However, time cannot be negative in this context, so we take the magnitude of the time, which is 0.06 s. Therefore, the time taken by the ball to come to rest is 0.06 s.
Hence, the correct answer is option C) 0.06 s.
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A resistive force of 16 N acts on a ball of mass 40 g continuously. If the initial velocity of the ball is 24 ms-1,the time taken by it to come to rest is:a)0.04 sb)0.08 sc)0.06 sd)0.02 sCorrect answer is option 'C'. Can you explain this answer? for Class 9 2025 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A resistive force of 16 N acts on a ball of mass 40 g continuously. If the initial velocity of the ball is 24 ms-1,the time taken by it to come to rest is:a)0.04 sb)0.08 sc)0.06 sd)0.02 sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 9 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A resistive force of 16 N acts on a ball of mass 40 g continuously. If the initial velocity of the ball is 24 ms-1,the time taken by it to come to rest is:a)0.04 sb)0.08 sc)0.06 sd)0.02 sCorrect answer is option 'C'. Can you explain this answer?.
A resistive force of 16 N acts on a ball of mass 40 g continuously. If the initial velocity of the ball is 24 ms-1,the time taken by it to come to rest is:a)0.04 sb)0.08 sc)0.06 sd)0.02 sCorrect answer is option 'C'. Can you explain this answer? for Class 9 2025 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A resistive force of 16 N acts on a ball of mass 40 g continuously. If the initial velocity of the ball is 24 ms-1,the time taken by it to come to rest is:a)0.04 sb)0.08 sc)0.06 sd)0.02 sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 9 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A resistive force of 16 N acts on a ball of mass 40 g continuously. If the initial velocity of the ball is 24 ms-1,the time taken by it to come to rest is:a)0.04 sb)0.08 sc)0.06 sd)0.02 sCorrect answer is option 'C'. Can you explain this answer?.
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