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Fe2+ -porphyrins fail to exhibit reversible oxygen transport and cannot differentiate CO from O2. However, the hemoglobin is free from both these pit falls. Among the following the correct set of statements is:
(A) Fe2+-porphyrins undergo μ-oxodimer formation and the same is prevented in case of the hemoglobin.
(B) Fe–CO bond strength is much low in case of hemoglobin when compared to the Fe2+ -porthyrins.
(C) While Fe–CO is linear, Fe–O2 is bent and is recognized by hemoglobin.
(D) The interlinked four monomeric units in the hemoglobin are responsible to overcome the pitfalls.
(B) Fe–CO bond strength is much low in case of hemoglobin when compared to the Fe2+ -porthyrins.
(C) While Fe–CO is linear, Fe–O2 is bent and is recognized by hemoglobin.
(D) The interlinked four monomeric units in the hemoglobin are responsible to overcome the pitfalls.
- a)A and B
- b)A and C
- c)C and D
- d)B and D
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
Fe2+ -porphyrins fail to exhibit reversible oxygen transport and canno...
Explanation:
Fe2-porphyrins and Hemoglobin:
- Fe2-porphyrins and hemoglobin both contain a heme group which consists of an iron atom bound to a porphyrin ring.
- Fe2-porphyrins are synthetic compounds while hemoglobin is a natural protein found in red blood cells.
- Fe2-porphyrins cannot differentiate between CO and O2 due to the lack of a specific binding site while hemoglobin can distinguish between the two gases.
- Fe2-porphyrins do not exhibit reversible oxygen transport, while hemoglobin can transport oxygen from the lungs to the tissues and carbon dioxide from the tissues to the lungs.
Bond Strength:
- The bond strength between Fe and CO is much lower in hemoglobin than in Fe2-porphyrins. This is due to the unique environment created by the protein structure of hemoglobin which weakens the bond between Fe and CO.
FeCO and FeO2:
- FeCO is a linear molecule while FeO2 is bent. This difference in geometry is due to the presence of two lone pairs on the oxygen atoms in FeO2.
- Hemoglobin recognizes the bent geometry of FeO2 and binds to it specifically, allowing for the transport of oxygen in the body.
Interlinked Monomeric Units:
- The interlinked four monomeric units in hemoglobin work together to overcome the pitfalls of Fe2-porphyrins.
- The protein structure of hemoglobin creates a specific binding site for oxygen, allowing for efficient oxygen transport in the body.
- The interlinked monomeric units also allow for the cooperative binding of oxygen, meaning that each oxygen molecule that binds to hemoglobin increases the affinity of the remaining sites for oxygen.
Therefore, option B is the correct answer as it correctly identifies the difference in bond strength between FeCO in hemoglobin and Fe2-porphyrins.
Fe2-porphyrins and Hemoglobin:
- Fe2-porphyrins and hemoglobin both contain a heme group which consists of an iron atom bound to a porphyrin ring.
- Fe2-porphyrins are synthetic compounds while hemoglobin is a natural protein found in red blood cells.
- Fe2-porphyrins cannot differentiate between CO and O2 due to the lack of a specific binding site while hemoglobin can distinguish between the two gases.
- Fe2-porphyrins do not exhibit reversible oxygen transport, while hemoglobin can transport oxygen from the lungs to the tissues and carbon dioxide from the tissues to the lungs.
Bond Strength:
- The bond strength between Fe and CO is much lower in hemoglobin than in Fe2-porphyrins. This is due to the unique environment created by the protein structure of hemoglobin which weakens the bond between Fe and CO.
FeCO and FeO2:
- FeCO is a linear molecule while FeO2 is bent. This difference in geometry is due to the presence of two lone pairs on the oxygen atoms in FeO2.
- Hemoglobin recognizes the bent geometry of FeO2 and binds to it specifically, allowing for the transport of oxygen in the body.
Interlinked Monomeric Units:
- The interlinked four monomeric units in hemoglobin work together to overcome the pitfalls of Fe2-porphyrins.
- The protein structure of hemoglobin creates a specific binding site for oxygen, allowing for efficient oxygen transport in the body.
- The interlinked monomeric units also allow for the cooperative binding of oxygen, meaning that each oxygen molecule that binds to hemoglobin increases the affinity of the remaining sites for oxygen.
Therefore, option B is the correct answer as it correctly identifies the difference in bond strength between FeCO in hemoglobin and Fe2-porphyrins.
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Community Answer
Fe2+ -porphyrins fail to exhibit reversible oxygen transport and canno...
Hemoglobin is free from both these pitfalls as because the globin chain around the Fe-porphyrin ring (as a whole hemoglobin ) maintains hydrophobic environment. Now the porphyrin system alone forms oxodimer when exposed to air (as globin chain is absent). So option A is correct and Option D is wrong. For option C it is a general phenomena of hemoglobin that O2 is bent (first Oxygen is linear to Fe but the 2nd one is 120 degree bent may be because of histidine residing there) but for CO it is linear. For option B, Fe-CO bond strength is very high ( because of its high affinity towards hemoglobin and doesn't easily get detached from the system, it has100 times more affinity than O2),which may be equal or greater than Fe-porphyrin bond strength. so the said option is incorrect. so collectively option B is correct.
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Fe2+ -porphyrins fail to exhibit reversible oxygen transport and cannot differentiate CO from O2. However, the hemoglobin is free from both these pit falls. Among the following the correct set of statements is:(A) Fe2+-porphyrins undergo μ-oxodimer formation and the same is prevented in case of the hemoglobin.(B) Fe–CO bond strength is much low in case of hemoglobin when compared to the Fe2+ -porthyrins.(C) While Fe–CO is linear, Fe–O2 is bent and is recognized by hemoglobin.(D) The interlinked four monomeric units in the hemoglobin are responsible to overcome the pitfalls.a)A and Bb)A and Cc)C and Dd)B and DCorrect answer is option 'B'. Can you explain this answer?
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Fe2+ -porphyrins fail to exhibit reversible oxygen transport and cannot differentiate CO from O2. However, the hemoglobin is free from both these pit falls. Among the following the correct set of statements is:(A) Fe2+-porphyrins undergo μ-oxodimer formation and the same is prevented in case of the hemoglobin.(B) Fe–CO bond strength is much low in case of hemoglobin when compared to the Fe2+ -porthyrins.(C) While Fe–CO is linear, Fe–O2 is bent and is recognized by hemoglobin.(D) The interlinked four monomeric units in the hemoglobin are responsible to overcome the pitfalls.a)A and Bb)A and Cc)C and Dd)B and DCorrect answer is option 'B'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Fe2+ -porphyrins fail to exhibit reversible oxygen transport and cannot differentiate CO from O2. However, the hemoglobin is free from both these pit falls. Among the following the correct set of statements is:(A) Fe2+-porphyrins undergo μ-oxodimer formation and the same is prevented in case of the hemoglobin.(B) Fe–CO bond strength is much low in case of hemoglobin when compared to the Fe2+ -porthyrins.(C) While Fe–CO is linear, Fe–O2 is bent and is recognized by hemoglobin.(D) The interlinked four monomeric units in the hemoglobin are responsible to overcome the pitfalls.a)A and Bb)A and Cc)C and Dd)B and DCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Fe2+ -porphyrins fail to exhibit reversible oxygen transport and cannot differentiate CO from O2. However, the hemoglobin is free from both these pit falls. Among the following the correct set of statements is:(A) Fe2+-porphyrins undergo μ-oxodimer formation and the same is prevented in case of the hemoglobin.(B) Fe–CO bond strength is much low in case of hemoglobin when compared to the Fe2+ -porthyrins.(C) While Fe–CO is linear, Fe–O2 is bent and is recognized by hemoglobin.(D) The interlinked four monomeric units in the hemoglobin are responsible to overcome the pitfalls.a)A and Bb)A and Cc)C and Dd)B and DCorrect answer is option 'B'. Can you explain this answer?.
Fe2+ -porphyrins fail to exhibit reversible oxygen transport and cannot differentiate CO from O2. However, the hemoglobin is free from both these pit falls. Among the following the correct set of statements is:(A) Fe2+-porphyrins undergo μ-oxodimer formation and the same is prevented in case of the hemoglobin.(B) Fe–CO bond strength is much low in case of hemoglobin when compared to the Fe2+ -porthyrins.(C) While Fe–CO is linear, Fe–O2 is bent and is recognized by hemoglobin.(D) The interlinked four monomeric units in the hemoglobin are responsible to overcome the pitfalls.a)A and Bb)A and Cc)C and Dd)B and DCorrect answer is option 'B'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Fe2+ -porphyrins fail to exhibit reversible oxygen transport and cannot differentiate CO from O2. However, the hemoglobin is free from both these pit falls. Among the following the correct set of statements is:(A) Fe2+-porphyrins undergo μ-oxodimer formation and the same is prevented in case of the hemoglobin.(B) Fe–CO bond strength is much low in case of hemoglobin when compared to the Fe2+ -porthyrins.(C) While Fe–CO is linear, Fe–O2 is bent and is recognized by hemoglobin.(D) The interlinked four monomeric units in the hemoglobin are responsible to overcome the pitfalls.a)A and Bb)A and Cc)C and Dd)B and DCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Fe2+ -porphyrins fail to exhibit reversible oxygen transport and cannot differentiate CO from O2. However, the hemoglobin is free from both these pit falls. Among the following the correct set of statements is:(A) Fe2+-porphyrins undergo μ-oxodimer formation and the same is prevented in case of the hemoglobin.(B) Fe–CO bond strength is much low in case of hemoglobin when compared to the Fe2+ -porthyrins.(C) While Fe–CO is linear, Fe–O2 is bent and is recognized by hemoglobin.(D) The interlinked four monomeric units in the hemoglobin are responsible to overcome the pitfalls.a)A and Bb)A and Cc)C and Dd)B and DCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Fe2+ -porphyrins fail to exhibit reversible oxygen transport and cannot differentiate CO from O2. However, the hemoglobin is free from both these pit falls. Among the following the correct set of statements is:(A) Fe2+-porphyrins undergo μ-oxodimer formation and the same is prevented in case of the hemoglobin.(B) Fe–CO bond strength is much low in case of hemoglobin when compared to the Fe2+ -porthyrins.(C) While Fe–CO is linear, Fe–O2 is bent and is recognized by hemoglobin.(D) The interlinked four monomeric units in the hemoglobin are responsible to overcome the pitfalls.a)A and Bb)A and Cc)C and Dd)B and DCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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