Which of the following expressions is true in case of sodium chloride ...
In face-centered cubic system, the inter ionic distance is given by rc + ra = a/2
rc = Radius of the cation
ra = Radius of the Anion.
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Which of the following expressions is true in case of sodium chloride ...
In Nacl Na is present in octahedral void..means at the edge n centere of cubic lattice where is chloride ion is corner plus face..so2(rc+ra)=aThis imply rc + ra=a/2
Which of the following expressions is true in case of sodium chloride ...
A/√2
The correct answer is d) rc ra = a/√2. The radius of the chloride ion (rc) is larger than the radius of the sodium ion (ra), and the sodium and chloride ions are arranged in a face-centered cubic lattice in the sodium chloride unit cell. Therefore, the distance between the centers of adjacent ions along a diagonal of the unit cell can be calculated using the Pythagorean theorem as: sqrt(2)a, where a is the length of the edge of the unit cell. This distance is equal to the sum of the radii of the sodium and chloride ions, so:
rc + ra = sqrt(2)a
Substituting rc = sqrt(2)a - ra, we get:
ra(sqrt(2)+1) = sqrt(2)a
ra = a/√2
Therefore, the expression rc ra = a/√2 is true for a sodium chloride unit cell.