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If standard potential of the reaction 2H2O(l) = O2(g, 1bar) + 4H+(aq) + 4e– is E° = –1.23 V. At 25°C and pH = 7, what is the oxidation potential of pure water according to this reaction:
- a)–0.410 V
- b)–2.620 V
- c)–0.817 V
- d)–0.410 V
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
If standard potential of the reaction 2H2O(l) = O2(g, 1bar) + 4H+(aq) ...
Option C :: -0.817 V
Just use Nernst's Equation to solve this ....
Just use Nernst's Equation to solve this ....
Community Answer
If standard potential of the reaction 2H2O(l) = O2(g, 1bar) + 4H+(aq) ...
Calculation of Oxidation Potential of Pure Water
Standard potential of the reaction: 2H2O(l) = O2(g, 1bar) 4H (aq) 4e is E = 1.23 V.
pH of pure water at 25°C is 7.
Oxidation potential of pure water can be calculated using the Nernst equation:
E = E° - (0.0592/n) log Q
where, E is the potential of the cell, E° is the standard electrode potential, n is the number of electrons transferred in the reaction, and Q is the reaction quotient.
In this case, n = 4 as 4 electrons are transferred in the reaction. The reaction quotient Q can be calculated using the equilibrium constant of water dissociation (Kw):
Kw = [H+][OH-] = 10^-14
At pH 7, [H+] = [OH-] = 10^-7 M
Therefore, Q = [H+]^4/[O2] = (10^-7)^4/(1 bar) = 10^-28 bar^-1
Substituting the values in the Nernst equation:
E = 1.23 V - (0.0592/4) log (10^-28) = 0.817 V
Therefore, the oxidation potential of pure water according to this reaction is 0.817 V.
Answer: Option C (0.817 V)
Standard potential of the reaction: 2H2O(l) = O2(g, 1bar) 4H (aq) 4e is E = 1.23 V.
pH of pure water at 25°C is 7.
Oxidation potential of pure water can be calculated using the Nernst equation:
E = E° - (0.0592/n) log Q
where, E is the potential of the cell, E° is the standard electrode potential, n is the number of electrons transferred in the reaction, and Q is the reaction quotient.
In this case, n = 4 as 4 electrons are transferred in the reaction. The reaction quotient Q can be calculated using the equilibrium constant of water dissociation (Kw):
Kw = [H+][OH-] = 10^-14
At pH 7, [H+] = [OH-] = 10^-7 M
Therefore, Q = [H+]^4/[O2] = (10^-7)^4/(1 bar) = 10^-28 bar^-1
Substituting the values in the Nernst equation:
E = 1.23 V - (0.0592/4) log (10^-28) = 0.817 V
Therefore, the oxidation potential of pure water according to this reaction is 0.817 V.
Answer: Option C (0.817 V)
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If standard potential of the reaction 2H2O(l) = O2(g, 1bar) + 4H+(aq) + 4e– is E° = –1.23 V. At 25°C and pH = 7, what is the oxidation potential of pure water according to this reaction:a)–0.410 Vb)–2.620 Vc)–0.817 Vd)–0.410 VCorrect answer is option 'C'. Can you explain this answer?
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If standard potential of the reaction 2H2O(l) = O2(g, 1bar) + 4H+(aq) + 4e– is E° = –1.23 V. At 25°C and pH = 7, what is the oxidation potential of pure water according to this reaction:a)–0.410 Vb)–2.620 Vc)–0.817 Vd)–0.410 VCorrect answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about If standard potential of the reaction 2H2O(l) = O2(g, 1bar) + 4H+(aq) + 4e– is E° = –1.23 V. At 25°C and pH = 7, what is the oxidation potential of pure water according to this reaction:a)–0.410 Vb)–2.620 Vc)–0.817 Vd)–0.410 VCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If standard potential of the reaction 2H2O(l) = O2(g, 1bar) + 4H+(aq) + 4e– is E° = –1.23 V. At 25°C and pH = 7, what is the oxidation potential of pure water according to this reaction:a)–0.410 Vb)–2.620 Vc)–0.817 Vd)–0.410 VCorrect answer is option 'C'. Can you explain this answer?.
If standard potential of the reaction 2H2O(l) = O2(g, 1bar) + 4H+(aq) + 4e– is E° = –1.23 V. At 25°C and pH = 7, what is the oxidation potential of pure water according to this reaction:a)–0.410 Vb)–2.620 Vc)–0.817 Vd)–0.410 VCorrect answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about If standard potential of the reaction 2H2O(l) = O2(g, 1bar) + 4H+(aq) + 4e– is E° = –1.23 V. At 25°C and pH = 7, what is the oxidation potential of pure water according to this reaction:a)–0.410 Vb)–2.620 Vc)–0.817 Vd)–0.410 VCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If standard potential of the reaction 2H2O(l) = O2(g, 1bar) + 4H+(aq) + 4e– is E° = –1.23 V. At 25°C and pH = 7, what is the oxidation potential of pure water according to this reaction:a)–0.410 Vb)–2.620 Vc)–0.817 Vd)–0.410 VCorrect answer is option 'C'. Can you explain this answer?.
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