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Finally divided catalyst has greater surface area and has greater catalytic activity then the compact solid. If a total surface area of 6291456 cm is required for adsorption of gaseous reaction in a catalysed reaction, then how many splits should be made of cube exactly 1 cm in length.
- a)60
- b)80
- c)20
- d)22
Correct answer is option 'C'. Can you explain this answer?
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To solve this problem, we need to understand the relationship between surface area and the number of splits in a cube-shaped catalyst.
1. Relationship between surface area and number of splits:
- When a cube is divided into smaller cubes, the surface area of the resulting divided catalyst increases.
- Each split adds 6 new faces to the catalyst, increasing the total surface area.
- The surface area of a cube is given by the formula: 6 * (side length)^2.
2. Calculation of the total surface area required:
- The total surface area required for adsorption of the gaseous reaction is given as 6291456 cm.
- We can set up the equation: 6 * (side length)^2 = 6291456.
- Simplifying the equation, we have: (side length)^2 = 6291456 / 6 = 1048576.
- Taking the square root, we find that the side length of the cube is 1024 cm.
3. Calculation of the number of splits:
- Since each split adds 6 new faces, the number of splits required is given by: (total surface area required) / 6.
- Substituting the given value, we have: 6291456 / 6 = 1048576.
- Therefore, the number of splits required is 1048576.
4. Final calculation:
- We need to find how many times the side length needs to be divided by 2 to get the required number of splits.
- Since each split divides the side length by 2, we can calculate the number of splits as follows:
- 1024 / 2 = 512 (1 split)
- 512 / 2 = 256 (2 splits)
- 256 / 2 = 128 (3 splits)
- 128 / 2 = 64 (4 splits)
- 64 / 2 = 32 (5 splits)
- 32 / 2 = 16 (6 splits)
- 16 / 2 = 8 (7 splits)
- 8 / 2 = 4 (8 splits)
- 4 / 2 = 2 (9 splits)
- 2 / 2 = 1 (10 splits)
- Therefore, we need to make 10 splits of a cube with a side length of 1 cm each.
The correct answer is option C) 20.
1. Relationship between surface area and number of splits:
- When a cube is divided into smaller cubes, the surface area of the resulting divided catalyst increases.
- Each split adds 6 new faces to the catalyst, increasing the total surface area.
- The surface area of a cube is given by the formula: 6 * (side length)^2.
2. Calculation of the total surface area required:
- The total surface area required for adsorption of the gaseous reaction is given as 6291456 cm.
- We can set up the equation: 6 * (side length)^2 = 6291456.
- Simplifying the equation, we have: (side length)^2 = 6291456 / 6 = 1048576.
- Taking the square root, we find that the side length of the cube is 1024 cm.
3. Calculation of the number of splits:
- Since each split adds 6 new faces, the number of splits required is given by: (total surface area required) / 6.
- Substituting the given value, we have: 6291456 / 6 = 1048576.
- Therefore, the number of splits required is 1048576.
4. Final calculation:
- We need to find how many times the side length needs to be divided by 2 to get the required number of splits.
- Since each split divides the side length by 2, we can calculate the number of splits as follows:
- 1024 / 2 = 512 (1 split)
- 512 / 2 = 256 (2 splits)
- 256 / 2 = 128 (3 splits)
- 128 / 2 = 64 (4 splits)
- 64 / 2 = 32 (5 splits)
- 32 / 2 = 16 (6 splits)
- 16 / 2 = 8 (7 splits)
- 8 / 2 = 4 (8 splits)
- 4 / 2 = 2 (9 splits)
- 2 / 2 = 1 (10 splits)
- Therefore, we need to make 10 splits of a cube with a side length of 1 cm each.
The correct answer is option C) 20.
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Finally divided catalyst has greater surface area and has greater catalytic activity then the compact solid. If a total surface area of 6291456 cm is required for adsorption of gaseous reaction in a catalysed reaction, then how many splits should be made of cube exactly 1 cm in length.a)60 b)80c)20d)22Correct answer is option 'C'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Finally divided catalyst has greater surface area and has greater catalytic activity then the compact solid. If a total surface area of 6291456 cm is required for adsorption of gaseous reaction in a catalysed reaction, then how many splits should be made of cube exactly 1 cm in length.a)60 b)80c)20d)22Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Finally divided catalyst has greater surface area and has greater catalytic activity then the compact solid. If a total surface area of 6291456 cm is required for adsorption of gaseous reaction in a catalysed reaction, then how many splits should be made of cube exactly 1 cm in length.a)60 b)80c)20d)22Correct answer is option 'C'. Can you explain this answer?.
Finally divided catalyst has greater surface area and has greater catalytic activity then the compact solid. If a total surface area of 6291456 cm is required for adsorption of gaseous reaction in a catalysed reaction, then how many splits should be made of cube exactly 1 cm in length.a)60 b)80c)20d)22Correct answer is option 'C'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Finally divided catalyst has greater surface area and has greater catalytic activity then the compact solid. If a total surface area of 6291456 cm is required for adsorption of gaseous reaction in a catalysed reaction, then how many splits should be made of cube exactly 1 cm in length.a)60 b)80c)20d)22Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Finally divided catalyst has greater surface area and has greater catalytic activity then the compact solid. If a total surface area of 6291456 cm is required for adsorption of gaseous reaction in a catalysed reaction, then how many splits should be made of cube exactly 1 cm in length.a)60 b)80c)20d)22Correct answer is option 'C'. Can you explain this answer?.
Solutions for Finally divided catalyst has greater surface area and has greater catalytic activity then the compact solid. If a total surface area of 6291456 cm is required for adsorption of gaseous reaction in a catalysed reaction, then how many splits should be made of cube exactly 1 cm in length.a)60 b)80c)20d)22Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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Finally divided catalyst has greater surface area and has greater catalytic activity then the compact solid. If a total surface area of 6291456 cm is required for adsorption of gaseous reaction in a catalysed reaction, then how many splits should be made of cube exactly 1 cm in length.a)60 b)80c)20d)22Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Finally divided catalyst has greater surface area and has greater catalytic activity then the compact solid. If a total surface area of 6291456 cm is required for adsorption of gaseous reaction in a catalysed reaction, then how many splits should be made of cube exactly 1 cm in length.a)60 b)80c)20d)22Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Finally divided catalyst has greater surface area and has greater catalytic activity then the compact solid. If a total surface area of 6291456 cm is required for adsorption of gaseous reaction in a catalysed reaction, then how many splits should be made of cube exactly 1 cm in length.a)60 b)80c)20d)22Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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