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From a waterfall, water is falling at the rate of 100 kg/s on the blades of a turbine. If the height of fall is 100 m, the power delivered to the turbine is
- a)100kW
- b)100W
- c)1kW
- d)10kW
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
From a waterfall, water is falling at the rate of 100 kg/s on the blad...
Power = work done / time taken
or P = mgh / t
P = (m/t) gh = 100 x 10 x 100 = 100 kW
Most Upvoted Answer
From a waterfall, water is falling at the rate of 100 kg/s on the blad...
Given:
- Rate of water falling on the turbine blades = 100 kg/s
- Height of fall = 100 m
To find:
- Power delivered to the turbine
Formula:
Power = mgh
Calculation:
Given that the rate of water falling on the turbine blades is 100 kg/s, we can find the mass of water falling per second.
Mass of water falling per second = 100 kg/s
The height of fall is given as 100 m. Using the formula for potential energy, we can find the potential energy of the water falling per second.
Potential energy per second = mgh = 100 kg/s * 9.8 m/s^2 * 100 m = 98000 J/s
Since power is the rate at which work is done or energy is transferred, the power delivered to the turbine is equal to the potential energy per second.
Therefore, the power delivered to the turbine = 98000 J/s
To convert the power from joules per second to kilowatts, we divide the power by 1000.
Power (in kilowatts) = 98000 J/s / 1000 = 98 kW
Hence, the power delivered to the turbine is 98 kW, which is closest to option A (100 kW).
- Rate of water falling on the turbine blades = 100 kg/s
- Height of fall = 100 m
To find:
- Power delivered to the turbine
Formula:
Power = mgh
Calculation:
Given that the rate of water falling on the turbine blades is 100 kg/s, we can find the mass of water falling per second.
Mass of water falling per second = 100 kg/s
The height of fall is given as 100 m. Using the formula for potential energy, we can find the potential energy of the water falling per second.
Potential energy per second = mgh = 100 kg/s * 9.8 m/s^2 * 100 m = 98000 J/s
Since power is the rate at which work is done or energy is transferred, the power delivered to the turbine is equal to the potential energy per second.
Therefore, the power delivered to the turbine = 98000 J/s
To convert the power from joules per second to kilowatts, we divide the power by 1000.
Power (in kilowatts) = 98000 J/s / 1000 = 98 kW
Hence, the power delivered to the turbine is 98 kW, which is closest to option A (100 kW).
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Community Answer
From a waterfall, water is falling at the rate of 100 kg/s on the blad...
Take g= 10m/s^2.m=100kg/second.which means time is 1second.height=10m.P= mgh/t.P= 100 kg× 10m/s ^2× 100m/1sec.P= 100000/1.P=100000.1k=1000.P= 100 kilo watt.
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From a waterfall, water is falling at the rate of 100 kg/s on the blades of a turbine. If the height of fall is 100 m, the power delivered to the turbine isa)100kWb)100Wc)1kWd)10kWCorrect answer is option 'A'. Can you explain this answer?
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