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The regular expression denote a language comprising all possible strings of even length over the alphabet (0, 1)
- a)1 + 0(1+0)*
- b)(0+1) (1+0)*
- c)(1+0)
- d)(00+0111+10)*
Correct answer is option 'D'. Can you explain this answer?
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The regular expression denote a language comprising all possible strin...
The condition is satisfied by 00 or 0111 or 10 or iterations of these.
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The regular expression denote a language comprising all possible strin...
The correct regular expression that denotes a language comprising all possible strings of even length over the alphabet (0, 1) is option 'D': (00 0111 10)*.
Explanation:
To understand why option 'D' is the correct regular expression, let's break it down and analyze it step by step.
1. (00 0111 10)
- This part of the regular expression describes a specific pattern: a string that starts with '00', followed by '0111', and ends with '10'. This pattern represents a substring of length 6, which is an even length.
2. (00 0111 10)*
- The asterisk (*) indicates that the pattern described in step 1 can repeat zero or more times. This means that the pattern can be repeated any number of times, including zero. As a result, this regular expression allows for multiple occurrences of the pattern.
For example, the regular expression matches the following strings:
- "00011110": The pattern is repeated only once, resulting in a string of even length.
- "0001111000011110": The pattern is repeated twice, resulting in a string of even length.
- "" (empty string): The pattern does not repeat, resulting in a string of length zero, which is also considered an even length.
In conclusion, option 'D' correctly represents a regular expression that denotes a language comprising all possible strings of even length over the alphabet (0, 1).
Explanation:
To understand why option 'D' is the correct regular expression, let's break it down and analyze it step by step.
1. (00 0111 10)
- This part of the regular expression describes a specific pattern: a string that starts with '00', followed by '0111', and ends with '10'. This pattern represents a substring of length 6, which is an even length.
2. (00 0111 10)*
- The asterisk (*) indicates that the pattern described in step 1 can repeat zero or more times. This means that the pattern can be repeated any number of times, including zero. As a result, this regular expression allows for multiple occurrences of the pattern.
For example, the regular expression matches the following strings:
- "00011110": The pattern is repeated only once, resulting in a string of even length.
- "0001111000011110": The pattern is repeated twice, resulting in a string of even length.
- "" (empty string): The pattern does not repeat, resulting in a string of length zero, which is also considered an even length.
In conclusion, option 'D' correctly represents a regular expression that denotes a language comprising all possible strings of even length over the alphabet (0, 1).
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The regular expression denote a language comprising all possible strings of even length over the alphabet (0, 1)a)1 + 0(1+0)*b)(0+1) (1+0)*c)(1+0)d)(00+0111+10)*Correct answer is option 'D'. Can you explain this answer?
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