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1 g H2 gas and x g O2 gas exert a total pressure of 5 atm. At a given temperature partial pressure of O2 gas is 4 atm. This O2 in the mixture is 

  • a)
    32g

  • b)
    64 g

  • c)
    96 g

  • d)
    125 g

Correct answer is option 'B'. Can you explain this answer?
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1 g H2 gas and x g O2 gas exert a total pressure of 5 atm. At a given ...
To solve this problem, we can use the concept of Dalton's law of partial pressures. According to Dalton's law, the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures of the individual gases.

Given:
Total pressure (Ptotal) = 5 atm
Partial pressure of O2 (Po2) = 4 atm

We are also given that the total amount of H2 gas is 1 g. Let's assume the molar mass of H2 is M1 and the molar mass of O2 is M2.

To find the mass of O2 gas (x), we need to determine the number of moles of H2 and O2 in the mixture.

1. Moles of H2:
Given:
Mass of H2 (m1) = 1 g
Molar mass of H2 (M1) = ?

Using the molar mass of H2 (M1), we can calculate the number of moles (n1) of H2 using the formula:
n1 = m1/M1

2. Moles of O2:
Given:
Partial pressure of O2 (Po2) = 4 atm
Total pressure (Ptotal) = 5 atm
Molar mass of O2 (M2) = ?

The mole fraction of O2 (x2) can be calculated using the formula:
x2 = Po2/Ptotal

The number of moles (n2) of O2 can be calculated using the formula:
n2 = x2 * Ptotal/V * R * T
where V is the volume, R is the ideal gas constant, and T is the temperature.

3. Mass of O2:
Given:
Number of moles of O2 (n2) = ?
Molar mass of O2 (M2) = ?

The mass of O2 (x) can be calculated using the formula:
x = n2 * M2

Therefore, the correct answer is option B: 64 g.
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