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A trolley T of mass 5 kg on a horizontal smooth surface is pulled by a load of 2 kg through a uniform rope ABC of length 2 m and mass 1 kg. As the load falls from BC = 0 to BC = 2 m, its acceleration (in m/s2) changes from
  • a)
    20/6 to 30/5
     
  • b)
    20/8 to 30/8
  • c)
    20/5 to 30/6
  • d)
    none of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A trolley T of mass 5 kg on a horizontal smooth surface is pulled by a...
Initial force = load x g = 2 x 10 = 20 N
∴ initial acceleration = Force/Mass =
Final force = (load + mass of the thread) x g = ( 2 + 1 ) x 10 = 30N
∴  Final acceleration = (30/8) m/s2
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Most Upvoted Answer
A trolley T of mass 5 kg on a horizontal smooth surface is pulled by a...
Answer is option B but I can't upload the solution SO I KEPT THE SOLUTION FOR THIS SUM IN MY PROFILEIF YOU WANT THE SOLUTION SEE MY PROFILE PICTURE IT'S TRUE
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A trolley T of mass 5 kg on a horizontal smooth surface is pulled by a load of 2 kg through a uniform rope ABC of length 2 m and mass 1 kg. As the load falls from BC = 0 to BC = 2 m, its acceleration (in m/s2) changes froma)20/6 to 30/5b)20/8 to 30/8c)20/5to 30/6d)none of theseCorrect answer is option 'B'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A trolley T of mass 5 kg on a horizontal smooth surface is pulled by a load of 2 kg through a uniform rope ABC of length 2 m and mass 1 kg. As the load falls from BC = 0 to BC = 2 m, its acceleration (in m/s2) changes froma)20/6 to 30/5b)20/8 to 30/8c)20/5to 30/6d)none of theseCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A trolley T of mass 5 kg on a horizontal smooth surface is pulled by a load of 2 kg through a uniform rope ABC of length 2 m and mass 1 kg. As the load falls from BC = 0 to BC = 2 m, its acceleration (in m/s2) changes froma)20/6 to 30/5b)20/8 to 30/8c)20/5to 30/6d)none of theseCorrect answer is option 'B'. Can you explain this answer?.
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