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When a projectile is thrown up at an angle θ to the ground, the time taken by it to rise and to fall are related as
  • a)
    time of rise can be less than or equal to time of fall
  • b)
    they are equal
  • c)
    time of rise < time of fall
  • d)
    time of rise > time of fall
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
When a projectile is thrown up at an angle θ to the ground, the t...
The time of fall or rise for a projectile depends upon its vertical component of initial velocity and the vertical acceleration. As the acceleration does not change and the motion of path is identical for the rise phase and the fall phase, we can easily deduce that time taken is also the same.
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Most Upvoted Answer
When a projectile is thrown up at an angle θ to the ground, the t...
When a projectile is thrown up at an angle, it follows a curved path called a parabola. The motion of the projectile can be described by considering its horizontal and vertical components separately.

The horizontal component of the projectile's motion remains constant and is determined by its initial velocity and angle of projection. This component determines how far the projectile will travel horizontally before hitting the ground.

The vertical component of the projectile's motion is affected by gravity. It starts with an initial vertical velocity and is then accelerated downward due to the force of gravity. As the projectile reaches its maximum height, its vertical velocity becomes zero, and then it starts to fall back down towards the ground.

The time taken for the projectile to reach its maximum height is equal to the time taken for it to return to the same height after reaching its maximum height.

The total time of flight for the projectile can be calculated using the time taken for it to reach its maximum height and the time taken for it to fall back to the ground.

The range of the projectile, which is the horizontal distance it travels, can be calculated using the initial velocity, angle of projection, and the time of flight.

The maximum height reached by the projectile can be calculated using the initial vertical velocity and the time taken for it to reach its maximum height.

The shape of the projectile's trajectory depends on the initial angle of projection. If the angle is 45 degrees, the range and maximum height will be at their maximum values. For angles above 45 degrees, the range will decrease while the maximum height will increase. For angles below 45 degrees, the range will increase while the maximum height will decrease.

Overall, when a projectile is thrown up at an angle, its motion can be analyzed by considering its horizontal and vertical components separately and taking into account the effects of gravity.
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Community Answer
When a projectile is thrown up at an angle θ to the ground, the t...
Both time intervals are equal...(usin∅/g)
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