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A die is tossed twice. The probability of getting 1, 2, 3 or 4 on the first toss and 4, 5, or 6 on the second toss is:​
  • a)
    2/5
  • b)
    1/2
  • c)
    1/3
  • d)
    1/9
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A die is tossed twice. The probability of getting 1, 2, 3 or 4 on the ...
In first toss p(1) +p(2) +p(3) +p(4) = 1/6+1/6 +1/6+1/6=4/6=2/3 similarly 1/2 for second toss total 2/3×1/2=1/3
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Community Answer
A die is tossed twice. The probability of getting 1, 2, 3 or 4 on the ...
First Toss numbers Probability=4/6 Second Toss numbers Probability=3/6 Therefore Total Probability =(4×3)/(6×6) We will Multiply both the probability as this is AND case. In EITHER OR case we add the probabilities.
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A die is tossed twice. The probability of getting 1, 2, 3 or 4 on the first toss and 4, 5, or 6 on the second toss is:​a)2/5b)1/2c)1/3d)1/9Correct answer is option 'C'. Can you explain this answer?
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