A reaction follows second order rate law, a)A plot of [A] versus t is a straight lineb)A plot of 1/[A] versus t is a straight linec)A plot of ln[A] versus t is a straight lined)A plot of e[A] versus t is a straight lineCorrect answer is option 'B'. Can you explain this answer?

Question

Answer

On integrating the equation from A to Ao, we get
-1/A + 1/Ao = kt
1/A = kt + 1/Ao
where,
y = 1/A
x = t
m = k

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