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Given, HCI (g) → H (g) + Cl (g) at 298 K (say temperature T K),
For
Q. Thus, for the given reaction  (at 0 K) is
  • a)
    428.136 kJ
  • b)
    -428.136 kJ
  • c)
    431.961 kJ
  • d)
    -431.961 kJ
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Given, HCI (g) → H (g) + Cl (g) at 298 K (say temperature T K),F...
Ho= Ho of product - Ho of reactant
so ho =(6.197 + 6.272 ) - 8.644
= 3.825
Ho298-Ho = 431.961 - 3.825=428.136532873
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Most Upvoted Answer
Given, HCI (g) → H (g) + Cl (g) at 298 K (say temperature T K),F...
Ho= Ho of product - Ho of reactant
so ho =(6.197 + 6.272 ) - 8.644
= 3.825
Ho298-Ho = 431.961 - 3.825=428.136532873
Free Test
Community Answer
Given, HCI (g) → H (g) + Cl (g) at 298 K (say temperature T K),F...
Ho= Ho of product - Ho of reactant
so ho =(6.197 + 6.272 ) - 8.644
= 3.825


Ho298-Ho = 431.961 - 3.825=428.136
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Given, HCI (g) → H (g) + Cl (g) at 298 K (say temperature T K),ForQ. Thus, for the given reaction(at 0 K) isa)428.136 kJb)-428.136 kJc)431.961 kJd)-431.961 kJCorrect answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Given, HCI (g) → H (g) + Cl (g) at 298 K (say temperature T K),ForQ. Thus, for the given reaction(at 0 K) isa)428.136 kJb)-428.136 kJc)431.961 kJd)-431.961 kJCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given, HCI (g) → H (g) + Cl (g) at 298 K (say temperature T K),ForQ. Thus, for the given reaction(at 0 K) isa)428.136 kJb)-428.136 kJc)431.961 kJd)-431.961 kJCorrect answer is option 'A'. Can you explain this answer?.
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