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Volume occupied by single CsCl ion pair in a crystal is 7.014 × 10–23 cm3. The smallest
Cs—Cs internuclear distance is equal to length of the side of the cube corresponding to volume of one CsCl ion pair. The smallest Cs to Cs internuclear distance is nearly:     
  • a)
    4.4 Å                              
  • b)
    4.3 Å                       
  • c)
    4.0 Å                     
  • d)
    4.5 Å
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Volume occupied by single CsCl ion pair in a crystal is 7.014 × ...
According to the given condition,

Edge length (a) = 3√Volumeof oneCsClion pair



So, the smallest Cs to Cs internuclear distance is nearly 4 �.
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Volume occupied by single CsCl ion pair in a crystal is 7.014 × 10–23 cm3. The smallestCs—Cs internuclear distance is equal to length of the side of the cube corresponding to volume of one CsCl ion pair. The smallest Cs to Cs internuclear distance is nearly: a)4.4 Åb)4.3 Åc)4.0 Åd)4.5 ÅCorrect answer is option 'C'. Can you explain this answer?
Question Description
Volume occupied by single CsCl ion pair in a crystal is 7.014 × 10–23 cm3. The smallestCs—Cs internuclear distance is equal to length of the side of the cube corresponding to volume of one CsCl ion pair. The smallest Cs to Cs internuclear distance is nearly: a)4.4 Åb)4.3 Åc)4.0 Åd)4.5 ÅCorrect answer is option 'C'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Volume occupied by single CsCl ion pair in a crystal is 7.014 × 10–23 cm3. The smallestCs—Cs internuclear distance is equal to length of the side of the cube corresponding to volume of one CsCl ion pair. The smallest Cs to Cs internuclear distance is nearly: a)4.4 Åb)4.3 Åc)4.0 Åd)4.5 ÅCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Volume occupied by single CsCl ion pair in a crystal is 7.014 × 10–23 cm3. The smallestCs—Cs internuclear distance is equal to length of the side of the cube corresponding to volume of one CsCl ion pair. The smallest Cs to Cs internuclear distance is nearly: a)4.4 Åb)4.3 Åc)4.0 Åd)4.5 ÅCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Volume occupied by single CsCl ion pair in a crystal is 7.014 × 10–23 cm3. The smallestCs—Cs internuclear distance is equal to length of the side of the cube corresponding to volume of one CsCl ion pair. The smallest Cs to Cs internuclear distance is nearly: a)4.4 Åb)4.3 Åc)4.0 Åd)4.5 ÅCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for IIT JAM. Download more important topics, notes, lectures and mock test series for IIT JAM Exam by signing up for free.
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