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Cos(-435°) =
  • a)
    cos15°
  • b)
    −cos15°
  • c)
    −sin15°
  • d)
    sin15°
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Cos(-435°) =a)cos15°b)−cos15°c)−sin15°d)si...
Since, cos(−x) = cosx
⇒ cos(−435°) = cos(435°)
= cos(360° + 75°)
= cos(75o)
= cos(90° − 15°)
=  sin15°
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Most Upvoted Answer
Cos(-435°) =a)cos15°b)−cos15°c)−sin15°d)si...
Cos(-a) is cosa so cos (-435)became cos 435then cos(360+75) so cos (75) if we rewrite in other form as cos (90-15)so by formula it becames sin15
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Community Answer
Cos(-435°) =a)cos15°b)−cos15°c)−sin15°d)si...
Explanation:

Given:
Angle = -435°

To find:
cos(-435°)

Approach:
We know that cosine function is an even function, which means cos(-x) = cos(x) for all x. Therefore, we can rewrite cos(-435°) as cos(435°) and find its value.

Solution:
-435° + 360° = -75°
cos(-435°) = cos(-75°)
Now, we can rewrite -75° as -90° + 15°, and use the cosine addition formula:
cos(a + b) = cos(a)cos(b) - sin(a)sin(b)
cos(-75°) = cos(-90° + 15°)
= cos(-90°)cos(15°) - sin(-90°)sin(15°)
= 0 - (-1)(sin15°)
= sin15°
Therefore, cos(-435°) = sin15°, which corresponds to option D) sin15°.
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Cos(-435°) =a)cos15°b)−cos15°c)−sin15°d)sin15°Correct answer is option 'D'. Can you explain this answer?
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