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The tetrachloro complexes of Ni(II) and Pd(II) respectively, are (atomic numbers of Ni and Pd are 28 and 46 respectively)
- a)diamagnetic and diamagnetic
- b)paramagnetic and paramagnetic
- c)diamagnetic and paramagnetic
- d)paramagnetic and diamagnetic
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The tetrachloro complexes of Ni(II) and Pd(II) respectively, are (atom...
[NiCl4]2– Paramagnetic
Pairing occurs in case of Pd sine it has greater nuclear charge leading to quater interaction to the ligands.
Correct option is (d)
Correct option is (d)
Most Upvoted Answer
The tetrachloro complexes of Ni(II) and Pd(II) respectively, are (atom...
Ni+2 = d8 system, pd+2= d8 system. Ni belongs to 3d metal and chloride is weak field legend. It is tetrahydral and paramagnetic.
Pd belongs to 4d metal,and anya legend with 4d & 5d metal behaves as strong field legend. Here pairing takes place. It is Squire planer complex and Diamagnetic.
So option D is correct.
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The tetrachloro complexes of Ni(II) and Pd(II) respectively, are (atom...
Tetrachloro complexes of Ni(II) and Pd(II) have different magnetic properties. The correct answer is option 'D', which states that the tetrachloro complex of Ni(II) is paramagnetic while the tetrachloro complex of Pd(II) is diamagnetic.
Explanation:
1. Paramagnetic:
- Paramagnetic substances have unpaired electrons.
- These substances are attracted by an external magnetic field due to the presence of unpaired electrons.
- Paramagnetism arises from the presence of one or more unpaired electrons in the d-orbitals of the metal ion.
2. Diamagnetic:
- Diamagnetic substances have all paired electrons.
- These substances are not attracted by an external magnetic field.
- Diamagnetism arises from the absence of unpaired electrons in the d-orbitals of the metal ion.
Tetrachloro Complexes:
- In the tetrachloro complexes of Ni(II) and Pd(II), the metal ions are coordinated with four chloride ions (Cl-) to form a square planar geometry.
- The electronic configuration of Ni(II) is [Ar] 3d8 4s2, and the electronic configuration of Pd(II) is [Kr] 4d8.
Magnetic Properties of Ni(II) Tetrachloro Complex:
- In the tetrachloro complex of Ni(II), there are two unpaired electrons in the d-orbitals ([Ar] 3d8).
- The presence of unpaired electrons makes the complex paramagnetic.
- Paramagnetic substances are attracted to an external magnetic field, indicating that the tetrachloro complex of Ni(II) will be paramagnetic.
Magnetic Properties of Pd(II) Tetrachloro Complex:
- In the tetrachloro complex of Pd(II), all the electrons in the d-orbitals are paired ([Kr] 4d8).
- The absence of unpaired electrons makes the complex diamagnetic.
- Diamagnetic substances are not attracted to an external magnetic field, indicating that the tetrachloro complex of Pd(II) will be diamagnetic.
Therefore, the correct answer is option 'D', which states that the tetrachloro complex of Ni(II) is paramagnetic while the tetrachloro complex of Pd(II) is diamagnetic.
Explanation:
1. Paramagnetic:
- Paramagnetic substances have unpaired electrons.
- These substances are attracted by an external magnetic field due to the presence of unpaired electrons.
- Paramagnetism arises from the presence of one or more unpaired electrons in the d-orbitals of the metal ion.
2. Diamagnetic:
- Diamagnetic substances have all paired electrons.
- These substances are not attracted by an external magnetic field.
- Diamagnetism arises from the absence of unpaired electrons in the d-orbitals of the metal ion.
Tetrachloro Complexes:
- In the tetrachloro complexes of Ni(II) and Pd(II), the metal ions are coordinated with four chloride ions (Cl-) to form a square planar geometry.
- The electronic configuration of Ni(II) is [Ar] 3d8 4s2, and the electronic configuration of Pd(II) is [Kr] 4d8.
Magnetic Properties of Ni(II) Tetrachloro Complex:
- In the tetrachloro complex of Ni(II), there are two unpaired electrons in the d-orbitals ([Ar] 3d8).
- The presence of unpaired electrons makes the complex paramagnetic.
- Paramagnetic substances are attracted to an external magnetic field, indicating that the tetrachloro complex of Ni(II) will be paramagnetic.
Magnetic Properties of Pd(II) Tetrachloro Complex:
- In the tetrachloro complex of Pd(II), all the electrons in the d-orbitals are paired ([Kr] 4d8).
- The absence of unpaired electrons makes the complex diamagnetic.
- Diamagnetic substances are not attracted to an external magnetic field, indicating that the tetrachloro complex of Pd(II) will be diamagnetic.
Therefore, the correct answer is option 'D', which states that the tetrachloro complex of Ni(II) is paramagnetic while the tetrachloro complex of Pd(II) is diamagnetic.
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The tetrachloro complexes of Ni(II) and Pd(II) respectively, are (atomic numbers of Ni and Pd are 28 and 46 respectively)a)diamagnetic and diamagneticb)paramagnetic and paramagneticc)diamagnetic and paramagneticd)paramagnetic and diamagneticCorrect answer is option 'D'. Can you explain this answer?
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