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a quantity of 10g of a hydrocarbon exactly requires 40g of oxygen for complete combustion the product formed are CO2 and water when CO2 gas formed is absorbed completely in lime water the mass of solution increase by 27.5g what is the mass of water formed in combustion?
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?a quantity of 10g of a hydrocarbon exactly requires 40g of oxygen for...

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?a quantity of 10g of a hydrocarbon exactly requires 40g of oxygen for...
Given information:
- Mass of hydrocarbon = 10g
- Mass of oxygen required for complete combustion = 40g
- Product formed: CO2 and water
- Absorption of CO2 in lime water leads to a mass increase of 27.5g

Calculating the mass of water formed:
1. Balance the chemical equation:
Assume the hydrocarbon is CxHy.
The balanced equation for complete combustion is:
CxHy + (x + y/4)O2 -> xCO2 + (y/2)H2O
2. Calculate moles of hydrocarbon and oxygen:
Moles of hydrocarbon = 10g / molar mass of hydrocarbon
Moles of oxygen = 40g / molar mass of oxygen
3. Calculate moles of water formed:
From the balanced equation, 1 mole of hydrocarbon produces y/2 moles of water.
Therefore, moles of water = (y/2) * moles of hydrocarbon
4. Calculate mass of water formed:
Mass of water = Moles of water * molar mass of water
5. Check the mass increase due to CO2 absorption:
The mass increase due to CO2 absorption is 27.5g.
This mass increase is equivalent to the mass of CO2 absorbed.
6. Calculate the moles of CO2 absorbed:
Moles of CO2 = 27.5g / molar mass of CO2
7. Convert moles of CO2 absorbed to moles of water formed:
From the balanced equation, 1 mole of CO2 corresponds to (y/2) moles of water.
8. Calculate the mass of water formed:
Mass of water = Moles of water * molar mass of water
Therefore, by following the steps above and using the given information, the mass of water formed during the combustion of the hydrocarbon can be accurately calculated.
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?a quantity of 10g of a hydrocarbon exactly requires 40g of oxygen for...
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