The inverse of isa)b)c)d)Correct answer is option 'B'. Can you explain this answer?

Question

Answer

A11=0A12=1A21=1A22=0A^-1=[01]          [10]

Answer

If we want inverse we have to make raw as column and column to raw

Answer

Wondering , which subject is this?

Answer

A = {(0,1) (1,0)}
Adj(A) = {(0,(-1)) ((-1),0)}
|A| = (0 - 1) = -1
A^-1 = adj(A)/|A|
= -1{(0,(-1)) ((-1),0)}
= {(0,1) (1,0)}

Answer

A = {(0,1) (1,0)}
Adj(A) = {(0,(-1)) ((-1),0)}
|A| = (0 - 1) = -1
A^-1 = adj(A)/|A|
= -1{(0,(-1)) ((-1),0)}
= {(0,1) (1,0)}