A cyclist of mass 30 kg exerts a force of 250 N to move his cycle. The acceleration is 4 ms−2. The force of friction between the road and tyres will bea)120 Nb)130 Nc)150Nd)115 NCorrect answer is option 'B'. Can you explain this answer?

Question

A cyclist of mass 30 kg exerts a force of 250 N to move his cycle. The acceleration is 4 ms&minus;2. The force of friction between the road and tyres will bea)120 Nb)130 Nc)150Nd)115 NCorrect answer is option 'B'. Can you explain this answer?

Answer

Here, resultant force =m×a=30×4=120N total force exerted=250N force of friction=250N-120N=130N so the correct answer is 130N(answer)

Answer

So , the resultant force = m× a = 30 × 4 = 120N now the total force exerted by the cyclist = 250N force of friction is equals to total force exerted - the resultant force so 250 Newton - 120 Newton is equals to 130 Newtons

Answer

To calculate the acceleration, we use Newton's second law of motion:

$$F = ma$$

where F is the force applied, m is the mass of the object, and a is the acceleration.

Given:
Mass (m) = 30 kg
Force (F) = 250 N

Plugging in the values, we can solve for acceleration (a):

$$250 N = 30 kg \times a$$

Dividing both sides of the equation by 30 kg:

$$a = \frac{250 N}{30 kg} = \frac{25}{3} \, \text{m/s}^2$$

Therefore, the acceleration of the cyclist is $\frac{25}{3} \, \text{m/s}^2$ or approximately 8.33 m/s².

Answer

Can someone explain that how did the mass of cyclist mattered whereas the object on which force is applied should be considered i.e of cycle not cyclist

Answer

B

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