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The observed oxidation state of lanthanides either in solution or in insoluble compounds form tripositive cations. Based on the ionisation enthalpies and hydration energy factors, it is concluded that tripositive species is more stable than di or tetrapositive species in aqueous solution. In general, ions having half-filled (Tb4+ , Eu2+ , Gd3+) or completely filled 4f orbitals (Yb2+, Lu3+) or noble gas configuration (La3+, Ce4+) are stable. This is supported by their SRP values. Ions with + 4 oxidation state act as oxidising and ions having + 2 oxidation state act as reducing agents. Ions having same number of unpaired electrons in f-orbitals possess same colour.
Q. Which is correct statement?
- a)Ce4+ is more stable than Ce3+ in solution
- b)Ce3+ is more sable than Ce4+ in solution
- c)Ce4+ and Ce3+ are equally stable
- d)Ce4+ has xenon configuration
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The observed oxidation state of lanthanides either in solution or in i...
Ce4+ is [Xe] 4f0, it tends to revert to more stable oxidation state of +3 by gain of an electron. That is why, in aqueous solution, Ce4+ is good oxidising agent.
Most Upvoted Answer
The observed oxidation state of lanthanides either in solution or in i...
The answer is itself in question... ce3+ has partially filled orbital but ce4+ has niether completely filled nor partially filled so, ce3+ is more stable than ce4+. always the stable form are partially or fully filled orbitals (last one)!!also +3 oxidation state is more stable than +4 oxidation state
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Community Answer
The observed oxidation state of lanthanides either in solution or in i...
The correct statement is: Ce3+ is more stable than Ce4+ in solution.
Explanation:
The given statement is based on the observed oxidation states of lanthanides and their stability in solution. According to the information provided, the observed oxidation state of lanthanides is tripositive (3+) in both solution and insoluble compounds. Tripositive species are found to be more stable than dipositive (2+) or tetrapositive (4+) species in aqueous solution.
Factors determining stability:
1. Ionization enthalpy: The ionization enthalpy refers to the energy required to remove an electron from an atom or ion in the gas phase. In the case of cerium (Ce), the ionization enthalpy of Ce3+ is lower than that of Ce4+. This indicates that it is easier to remove an electron from Ce3+ to form Ce4+.
2. Hydration energy: The hydration energy refers to the energy released when an ion is hydrated or surrounded by water molecules. The hydration energy of Ce3+ is higher than that of Ce4+. This indicates that Ce3+ ions are more strongly hydrated in solution.
3. Stability based on electronic configuration: Ce4+ has an electron configuration of [Xe]4f0, which is not stable. On the other hand, Ce3+ has an electron configuration of [Xe]4f1, which is more stable due to the presence of an unpaired electron.
Conclusion:
Based on the ionization enthalpies and hydration energy factors, it can be concluded that Ce3+ is more stable than Ce4+ in solution. Ce3+ ions are more stable due to their lower ionization enthalpy, higher hydration energy, and the presence of an unpaired electron in the 4f orbital.
Therefore, the correct statement is option 'B': Ce3+ is more stable than Ce4+ in solution.
Explanation:
The given statement is based on the observed oxidation states of lanthanides and their stability in solution. According to the information provided, the observed oxidation state of lanthanides is tripositive (3+) in both solution and insoluble compounds. Tripositive species are found to be more stable than dipositive (2+) or tetrapositive (4+) species in aqueous solution.
Factors determining stability:
1. Ionization enthalpy: The ionization enthalpy refers to the energy required to remove an electron from an atom or ion in the gas phase. In the case of cerium (Ce), the ionization enthalpy of Ce3+ is lower than that of Ce4+. This indicates that it is easier to remove an electron from Ce3+ to form Ce4+.
2. Hydration energy: The hydration energy refers to the energy released when an ion is hydrated or surrounded by water molecules. The hydration energy of Ce3+ is higher than that of Ce4+. This indicates that Ce3+ ions are more strongly hydrated in solution.
3. Stability based on electronic configuration: Ce4+ has an electron configuration of [Xe]4f0, which is not stable. On the other hand, Ce3+ has an electron configuration of [Xe]4f1, which is more stable due to the presence of an unpaired electron.
Conclusion:
Based on the ionization enthalpies and hydration energy factors, it can be concluded that Ce3+ is more stable than Ce4+ in solution. Ce3+ ions are more stable due to their lower ionization enthalpy, higher hydration energy, and the presence of an unpaired electron in the 4f orbital.
Therefore, the correct statement is option 'B': Ce3+ is more stable than Ce4+ in solution.
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The observed oxidation state of lanthanides either in solution or in insoluble compounds form tripositive cations. Based on the ionisation enthalpies and hydration energy factors, it is concluded that tripositive species is more stable than di or tetrapositive species in aqueous solution. In general, ions having half-filled (Tb4+ , Eu2+ , Gd3+) or completely filled 4f orbitals (Yb2+, Lu3+) or noble gas configuration (La3+, Ce4+) are stable. This is supported by their SRP values. Ions with + 4 oxidation state act as oxidising and ions having + 2 oxidation state act as reducing agents. Ions having same number of unpaired electrons in f-orbitals possess same colour.Q.Which is correct statement?a)Ce4+ is more stable than Ce3+ in solutionb)Ce3+ is more sable than Ce4+ in solutionc)Ce4+ and Ce3+ are equally stabled)Ce4+ has xenon configurationCorrect answer is option 'B'. Can you explain this answer?
Question Description
The observed oxidation state of lanthanides either in solution or in insoluble compounds form tripositive cations. Based on the ionisation enthalpies and hydration energy factors, it is concluded that tripositive species is more stable than di or tetrapositive species in aqueous solution. In general, ions having half-filled (Tb4+ , Eu2+ , Gd3+) or completely filled 4f orbitals (Yb2+, Lu3+) or noble gas configuration (La3+, Ce4+) are stable. This is supported by their SRP values. Ions with + 4 oxidation state act as oxidising and ions having + 2 oxidation state act as reducing agents. Ions having same number of unpaired electrons in f-orbitals possess same colour.Q.Which is correct statement?a)Ce4+ is more stable than Ce3+ in solutionb)Ce3+ is more sable than Ce4+ in solutionc)Ce4+ and Ce3+ are equally stabled)Ce4+ has xenon configurationCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The observed oxidation state of lanthanides either in solution or in insoluble compounds form tripositive cations. Based on the ionisation enthalpies and hydration energy factors, it is concluded that tripositive species is more stable than di or tetrapositive species in aqueous solution. In general, ions having half-filled (Tb4+ , Eu2+ , Gd3+) or completely filled 4f orbitals (Yb2+, Lu3+) or noble gas configuration (La3+, Ce4+) are stable. This is supported by their SRP values. Ions with + 4 oxidation state act as oxidising and ions having + 2 oxidation state act as reducing agents. Ions having same number of unpaired electrons in f-orbitals possess same colour.Q.Which is correct statement?a)Ce4+ is more stable than Ce3+ in solutionb)Ce3+ is more sable than Ce4+ in solutionc)Ce4+ and Ce3+ are equally stabled)Ce4+ has xenon configurationCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The observed oxidation state of lanthanides either in solution or in insoluble compounds form tripositive cations. Based on the ionisation enthalpies and hydration energy factors, it is concluded that tripositive species is more stable than di or tetrapositive species in aqueous solution. In general, ions having half-filled (Tb4+ , Eu2+ , Gd3+) or completely filled 4f orbitals (Yb2+, Lu3+) or noble gas configuration (La3+, Ce4+) are stable. This is supported by their SRP values. Ions with + 4 oxidation state act as oxidising and ions having + 2 oxidation state act as reducing agents. Ions having same number of unpaired electrons in f-orbitals possess same colour.Q.Which is correct statement?a)Ce4+ is more stable than Ce3+ in solutionb)Ce3+ is more sable than Ce4+ in solutionc)Ce4+ and Ce3+ are equally stabled)Ce4+ has xenon configurationCorrect answer is option 'B'. Can you explain this answer?.
The observed oxidation state of lanthanides either in solution or in insoluble compounds form tripositive cations. Based on the ionisation enthalpies and hydration energy factors, it is concluded that tripositive species is more stable than di or tetrapositive species in aqueous solution. In general, ions having half-filled (Tb4+ , Eu2+ , Gd3+) or completely filled 4f orbitals (Yb2+, Lu3+) or noble gas configuration (La3+, Ce4+) are stable. This is supported by their SRP values. Ions with + 4 oxidation state act as oxidising and ions having + 2 oxidation state act as reducing agents. Ions having same number of unpaired electrons in f-orbitals possess same colour.Q.Which is correct statement?a)Ce4+ is more stable than Ce3+ in solutionb)Ce3+ is more sable than Ce4+ in solutionc)Ce4+ and Ce3+ are equally stabled)Ce4+ has xenon configurationCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The observed oxidation state of lanthanides either in solution or in insoluble compounds form tripositive cations. Based on the ionisation enthalpies and hydration energy factors, it is concluded that tripositive species is more stable than di or tetrapositive species in aqueous solution. In general, ions having half-filled (Tb4+ , Eu2+ , Gd3+) or completely filled 4f orbitals (Yb2+, Lu3+) or noble gas configuration (La3+, Ce4+) are stable. This is supported by their SRP values. Ions with + 4 oxidation state act as oxidising and ions having + 2 oxidation state act as reducing agents. Ions having same number of unpaired electrons in f-orbitals possess same colour.Q.Which is correct statement?a)Ce4+ is more stable than Ce3+ in solutionb)Ce3+ is more sable than Ce4+ in solutionc)Ce4+ and Ce3+ are equally stabled)Ce4+ has xenon configurationCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The observed oxidation state of lanthanides either in solution or in insoluble compounds form tripositive cations. Based on the ionisation enthalpies and hydration energy factors, it is concluded that tripositive species is more stable than di or tetrapositive species in aqueous solution. In general, ions having half-filled (Tb4+ , Eu2+ , Gd3+) or completely filled 4f orbitals (Yb2+, Lu3+) or noble gas configuration (La3+, Ce4+) are stable. This is supported by their SRP values. Ions with + 4 oxidation state act as oxidising and ions having + 2 oxidation state act as reducing agents. Ions having same number of unpaired electrons in f-orbitals possess same colour.Q.Which is correct statement?a)Ce4+ is more stable than Ce3+ in solutionb)Ce3+ is more sable than Ce4+ in solutionc)Ce4+ and Ce3+ are equally stabled)Ce4+ has xenon configurationCorrect answer is option 'B'. Can you explain this answer?.
Solutions for The observed oxidation state of lanthanides either in solution or in insoluble compounds form tripositive cations. Based on the ionisation enthalpies and hydration energy factors, it is concluded that tripositive species is more stable than di or tetrapositive species in aqueous solution. In general, ions having half-filled (Tb4+ , Eu2+ , Gd3+) or completely filled 4f orbitals (Yb2+, Lu3+) or noble gas configuration (La3+, Ce4+) are stable. This is supported by their SRP values. Ions with + 4 oxidation state act as oxidising and ions having + 2 oxidation state act as reducing agents. Ions having same number of unpaired electrons in f-orbitals possess same colour.Q.Which is correct statement?a)Ce4+ is more stable than Ce3+ in solutionb)Ce3+ is more sable than Ce4+ in solutionc)Ce4+ and Ce3+ are equally stabled)Ce4+ has xenon configurationCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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Here you can find the meaning of The observed oxidation state of lanthanides either in solution or in insoluble compounds form tripositive cations. Based on the ionisation enthalpies and hydration energy factors, it is concluded that tripositive species is more stable than di or tetrapositive species in aqueous solution. In general, ions having half-filled (Tb4+ , Eu2+ , Gd3+) or completely filled 4f orbitals (Yb2+, Lu3+) or noble gas configuration (La3+, Ce4+) are stable. This is supported by their SRP values. Ions with + 4 oxidation state act as oxidising and ions having + 2 oxidation state act as reducing agents. Ions having same number of unpaired electrons in f-orbitals possess same colour.Q.Which is correct statement?a)Ce4+ is more stable than Ce3+ in solutionb)Ce3+ is more sable than Ce4+ in solutionc)Ce4+ and Ce3+ are equally stabled)Ce4+ has xenon configurationCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The observed oxidation state of lanthanides either in solution or in insoluble compounds form tripositive cations. Based on the ionisation enthalpies and hydration energy factors, it is concluded that tripositive species is more stable than di or tetrapositive species in aqueous solution. In general, ions having half-filled (Tb4+ , Eu2+ , Gd3+) or completely filled 4f orbitals (Yb2+, Lu3+) or noble gas configuration (La3+, Ce4+) are stable. This is supported by their SRP values. Ions with + 4 oxidation state act as oxidising and ions having + 2 oxidation state act as reducing agents. Ions having same number of unpaired electrons in f-orbitals possess same colour.Q.Which is correct statement?a)Ce4+ is more stable than Ce3+ in solutionb)Ce3+ is more sable than Ce4+ in solutionc)Ce4+ and Ce3+ are equally stabled)Ce4+ has xenon configurationCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for The observed oxidation state of lanthanides either in solution or in insoluble compounds form tripositive cations. Based on the ionisation enthalpies and hydration energy factors, it is concluded that tripositive species is more stable than di or tetrapositive species in aqueous solution. In general, ions having half-filled (Tb4+ , Eu2+ , Gd3+) or completely filled 4f orbitals (Yb2+, Lu3+) or noble gas configuration (La3+, Ce4+) are stable. This is supported by their SRP values. Ions with + 4 oxidation state act as oxidising and ions having + 2 oxidation state act as reducing agents. Ions having same number of unpaired electrons in f-orbitals possess same colour.Q.Which is correct statement?a)Ce4+ is more stable than Ce3+ in solutionb)Ce3+ is more sable than Ce4+ in solutionc)Ce4+ and Ce3+ are equally stabled)Ce4+ has xenon configurationCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of The observed oxidation state of lanthanides either in solution or in insoluble compounds form tripositive cations. Based on the ionisation enthalpies and hydration energy factors, it is concluded that tripositive species is more stable than di or tetrapositive species in aqueous solution. In general, ions having half-filled (Tb4+ , Eu2+ , Gd3+) or completely filled 4f orbitals (Yb2+, Lu3+) or noble gas configuration (La3+, Ce4+) are stable. This is supported by their SRP values. Ions with + 4 oxidation state act as oxidising and ions having + 2 oxidation state act as reducing agents. Ions having same number of unpaired electrons in f-orbitals possess same colour.Q.Which is correct statement?a)Ce4+ is more stable than Ce3+ in solutionb)Ce3+ is more sable than Ce4+ in solutionc)Ce4+ and Ce3+ are equally stabled)Ce4+ has xenon configurationCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The observed oxidation state of lanthanides either in solution or in insoluble compounds form tripositive cations. Based on the ionisation enthalpies and hydration energy factors, it is concluded that tripositive species is more stable than di or tetrapositive species in aqueous solution. In general, ions having half-filled (Tb4+ , Eu2+ , Gd3+) or completely filled 4f orbitals (Yb2+, Lu3+) or noble gas configuration (La3+, Ce4+) are stable. This is supported by their SRP values. Ions with + 4 oxidation state act as oxidising and ions having + 2 oxidation state act as reducing agents. Ions having same number of unpaired electrons in f-orbitals possess same colour.Q.Which is correct statement?a)Ce4+ is more stable than Ce3+ in solutionb)Ce3+ is more sable than Ce4+ in solutionc)Ce4+ and Ce3+ are equally stabled)Ce4+ has xenon configurationCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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