An electron falls from one energy level to another; it releases a cert...
E = h.v
= 6.63 x 10^-34 x 5.1 x 10^14
= 33.8 x 10^-20 J
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An electron falls from one energy level to another; it releases a cert...
Given information:
- Frequency of light released: 5.100 x 10^14 Hz
To determine the energy associated with the electron, we can use the equation:
E = h * f
where E is the energy, h is Planck's constant (6.626 x 10^-34 J·s), and f is the frequency of light.
Let's calculate the energy:
E = (6.626 x 10^-34 J·s) * (5.100 x 10^14 Hz)
Calculating this equation, we get:
E = 3.37626 x 10^-19 J
However, the options provided in the question are given in different units (Joules and kilojoules). So, let's convert the energy to the desired unit.
We know that 1 kJ = 1000 J, so to convert the energy from Joules to kilojoules, we divide the energy by 1000:
E = (3.37626 x 10^-19 J) / 1000
E = 3.37626 x 10^-22 kJ
Comparing this value to the options given, we see that option C is the closest match:
c) 33.8 x 10^-20 J
However, the given answer is not exactly the same as our calculated value. It seems there might be a typo in the provided options. The correct answer should be 3.38 x 10^-22 kJ, matching our calculated value.
An electron falls from one energy level to another; it releases a cert...
According to formula...E = hv... u can get the answer....
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