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Which gas will be more readily adsorbed on charcoal lump. ammonia or carbon dioxide and why?
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Which gas will be more readily adsorbed on charcoal lump. ammonia or c...
The amount of gas adsorbed depends upon the nature of gas. A gas with a higher critical temperature i.e. a more easily liquefiable gas is adsorbed to a greater extent. Critical temperature for ammonia is 406K while that for CO2 is 304 K.
In terms of Van derWaal’s forces, the substance with higher VanderWaal’s forces of attraction is more easily adsorbed. Ammonia molecules are hydrogen bonded to each other while carbondioxide molecules are held together by weak dipole-dipole interactions.
NH3 has higher critical temperature and larger VanderWaal’s forces of attraction than CO2 and therefore it will be adsorbed more readily than CO2.
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Which gas will be more readily adsorbed on charcoal lump. ammonia or carbon dioxide and why?
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Which gas will be more readily adsorbed on charcoal lump. ammonia or carbon dioxide and why? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Which gas will be more readily adsorbed on charcoal lump. ammonia or carbon dioxide and why? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which gas will be more readily adsorbed on charcoal lump. ammonia or carbon dioxide and why?.
Which gas will be more readily adsorbed on charcoal lump. ammonia or carbon dioxide and why? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Which gas will be more readily adsorbed on charcoal lump. ammonia or carbon dioxide and why? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which gas will be more readily adsorbed on charcoal lump. ammonia or carbon dioxide and why?.
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