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AB crystallizes in a body centred cubic lattice with edge length 'a' equal to 387 pm. The distance between two oppositely charged ions in the lattice is
  • a)
    300 pm
  • b)
    335 pm
  • c)
    250 pm
  • d)
    200 pm
Correct answer is option 'B'. Can you explain this answer?
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AB crystallizes in a body centred cubic lattice with edge length '...

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AB crystallizes in a body centred cubic lattice with edge length '...
Body-Centered Cubic Lattice

AB crystalizes in a body-centered cubic lattice (BCC). In this structure, each atom is located at the center of a cube and one atom is located at the center of the cube. This results in a lattice with a coordination number of 8.

Edge Length of the Lattice

The edge length of the lattice, a, is given as 387 pm.

Distance between Oppositely Charged Ions

The distance between oppositely charged ions in the lattice can be calculated using the formula:

d = a * sqrt(3) / 4

where d is the distance between the ions.

Substituting the given values, we get:

d = 387 pm * sqrt(3) / 4
d = 334.71 pm

Rounding off the answer, we get the correct option as B) 335 pm.
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AB crystallizes in a body centred cubic lattice with edge length '...
For body centred cubic (bcc) lattice, distance between two oppositely charged ions,

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AB crystallizes in a body centred cubic lattice with edge length 'a' equal to 387 pm. The distance between two oppositely charged ions in the lattice isa)300 pmb)335 pmc)250 pmd)200 pmCorrect answer is option 'B'. Can you explain this answer?
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